Question

Please help ASAP!!!!!!!!!!

Answer 1

Answer:

C

Step-by-step explanation:

assuming point (0,0) is D

let assume mid point of line DA is E

so x and y coordinate of point E

(x , y) = ( (4m+0)/2, (4n +0)/2 )

(x, y ) = ( 2m, 2n)

let assume F is the midpoint of line BC

so coordinates of point F is

(x , y) = ( (4q+4p)/2 , (4n+0)/2 )

(x , y ) = (2q+2p, 2n)

so now the coordinate or midpoint of mid segment EF is

(x , y) = ( (2m+2q+2p)/2, (2n+2n)/2 )

(x , y) = (m+q+p, 2n)