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neonofarm [45]
3 years ago
12

How does your model represent the problem?

Mathematics
1 answer:
Paha777 [63]3 years ago
8 0

Answer:

the first equation is the total legs on one dog being added together with 2 other total dog legs. The second equation is the number of dogs multiplied by the total number of legs on one dog. Either way both equation show 3 dogs with 4 legs each.

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8. Find the value of x so that line mis parallel to line l. (1 p<br><br> (3x+21)°<br><br> (4x-7)
dybincka [34]

Answer: The value of x is 28.

Step-by-step explanation:

Since line m is parallel to line l.

So, we assume that

(3x+21)° and (4x-7)° are corresponding angles.

And we know that , corresponding angles formed when a transversal cut the  parallel line are equal.

So, they must be equal to each other.

3x+21=4x-7\\\\21+7=4x-3x\\\\28^\circ=x

Hence, the value of x is 28.

6 0
3 years ago
Please Help! In which of the following intervals does the trigonometric inequality sec(x)
timofeeve [1]

Step-by-step explanation:

sec(x) = 1/cos(x)

cot(x) = cos(x)/sin(x)

sec is smaller than cot, if cos is negative (making sec negative) and sin is negative (making cot positive).

and that is true for the third quadrant.

which is pi < x < 3×pi/2

so, the third answer is right.

3 0
2 years ago
I need help like really bad.
Lelechka [254]

Answer:

PEMDAS

Step-by-step explanation:

parenthesis

Exponents

Multiply

Divide

Add

Subtract

6 0
3 years ago
A random sample of 49 measurements from one population had a sample mean of 15, with sample standard deviation 5. An independent
kotykmax [81]

Answer:

Comparing the p value with the significance level \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.  

Step-by-step explanation:

\bar X_{1}=15 represent the mean for sample 1

\bar X_{2}=18 represent the mean for sample 2

s_{1}=5 represent the sample standard deviation for 1  

s_{f}=6 represent the sample standard deviation for 2  

n_{1}=49 sample size for the group 2  

n_{2}=64 sample size for the group 2  

\alpha=0.01 Significance level provided

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:  

Null hypothesis:\mu_{1}-\mu_{2}=0  

Alternative hypothesis:\mu_{1} - \mu_{2}\neq 0  

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

And the degrees of freedom are given by df=n_1 +n_2 -2=49+64-2=111  

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:  

t=\frac{(15-18)-0}{\sqrt{\frac{5^2}{49}+\frac{6^2}{64}}}}=-2.897

P value

Since is a bilateral test the p value would be:  

p_v =2*P(t_{111}  

Comparing the p value with the significance level \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.  

7 0
3 years ago
Eric surveyed 22 shoppers in the supermarket bakery section about their purchasing habits is the sample of the shoppers at the s
Mazyrski [523]

jbdfvhgrsnDIUYYYYYYYYYYYYYYYYYYYZFIUuuuuuuuuuuuuuuuuuuuuuuuuuuuuuub

8 0
3 years ago
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