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cluponka [151]
3 years ago
6

I am the largest number that rounds to 241.699 when rounded to the nearest thousandth. What number am I? Please explain how you

did it im stumped
Mathematics
1 answer:
slava [35]3 years ago
4 0
For the answer to the question above asking <span>the largest number that rounds to 241.699 when rounding to the nearest thousandth. What number am I? I think the a</span><span>nswer  is 241.6994 (241.6995 would be rounded UP to 241.700).
</span>I hope my answer helped you.
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2 years ago
factorise the following 1. x²-2x+15.... 2. y²-19y+90​
Marta_Voda [28]

Answer:

1. x²-2x+15

This can't be factored, I've tried multiple ways now, but it just can't be factored.

2. y²-19y+90​

Let's factor y^2−19y+90

y^2−19y+90

The middle number is -19 and the last number is 90.

Factoring means we want something like

(y+_)(y+_)

Which numbers go in the blanks?

We need two numbers that...

   Add together to get -19

   Multiply together to get 90

Can you think of the two numbers?

Try -9 and -10:

   -9+-10 = -19

   -9*-10 = 90

Fill in the blanks in

(y+_)(y+_)

with -9 and -10 to get...

(y-9)(y-10)

Answer:

(y−9) (y−10)

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2 years ago
This is the longest side of a right triangle. It is also the side directly across from the 90-degree angle of a right triangle.
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Answer:

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Step-by-step explanation:

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3 years ago
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