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malfutka [58]
3 years ago
5

In a region where 48% of the population is male, there are 11 boys and 14 girls in a sample of children. What is p and ^p for ma

les, and p and ^p for females? P males= _____ ^p males=______ and p females=______ ^p females=______ can show me how this works to it's confusing me. Thank you
Mathematics
1 answer:
vekshin13 years ago
3 0
P male(sample proportion) = 11/(11 + 14) = 11/25 = 0.44
^p male(population proportion) = 48% = 0.48

p female(sample proportion) = 14/(11 + 14) = 0.56
^p female (population proportion) = 100 - 48 = 52% = 0.52
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A circle has a sector with area 27 and central angle of 120
Alex_Xolod [135]

Answer:

81π

Step-by-step explanation:

-The sum of central angles in a  circle add up to 360°.

-Let x be the area of the circle.

-Given the area of a 120° is 27π, the circles area can be calculated as:

A=27\pi\\\\120\textdegree=27\pi\\360\textdegree=x\\\\\therefore x=\frac{360\textdegree\times 27\pi}{120\textdegree}\\\\=3\times 27\pi\\\\=81\pi

Hence, the area of the circle is 81π

6 0
3 years ago
What two numbers multiply to get -15 but add together to get -2?
damaskus [11]

Answer:

-5,3

Step-by-step explanation:

-5x3=-15

-5+3=-2

4 0
3 years ago
A shopkeeper buys a dress for $40
DanielleElmas [232]

Answer:

48 - 40 = $8, there is a $8 dollar increase.

Formula for change of percentage;

changed price

___________ x 100% (100/100)

original amount

Replace those values with the values we found;

40/48 x 100/100 = 20% increase.

4 0
2 years ago
Can someone explain to me this derivative : y=3x√x
dimaraw [331]

Answer:

(9/2)√x.

Step-by-step explanation:

Convert the radical to an exponent.

x√x = x^1 * x^1/2

= x^(1 + 1/2)

= x^3/2

So the derivative of 3x^3/2 is found as follows:

y' = 3 * 3/2x^(3/2 - 1)

= (9/2)x^1/2

= (9/2)√x.

6 0
3 years ago
Radioactive Decay:
Vadim26 [7]

The question is incomplete, here is the complete question:

The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.

When will there be less than 1 g remaining?

<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.

<u>Step-by-step explanation:</u>

All radioactive decay processes follow first order reaction.

To calculate the rate constant by given half life of the reaction, we use the equation:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half life period of the reaction = 46 days

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{46days}\\\\k=0.01506days^{-1}

The formula used to calculate the time period for a first order reaction follows:

t=\frac{2.303}{k}\log \frac{a}{(a-x)}

where,

k = rate constant = 0.01506days^{-1}

t = time period = ? days

a = initial concentration of the reactant = 12.6 g

a - x = concentration of reactant left after time 't' = 1 g

Putting values in above equation, we get:

t=\frac{2.303}{0.01506days^{-1}}\log \frac{12.6g}{1g}\\\\t=168.27days

Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.

7 0
3 years ago
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