Answer:
81π
Step-by-step explanation:
-The sum of central angles in a circle add up to 360°.
-Let x be the area of the circle.
-Given the area of a 120° is 27π, the circles area can be calculated as:

Hence, the area of the circle is 81π
Answer:
-5,3
Step-by-step explanation:
-5x3=-15
-5+3=-2
Answer:
48 - 40 = $8, there is a $8 dollar increase.
Formula for change of percentage;
changed price
___________ x 100% (100/100)
original amount
Replace those values with the values we found;
40/48 x 100/100 = 20% increase.
Answer:
(9/2)√x.
Step-by-step explanation:
Convert the radical to an exponent.
x√x = x^1 * x^1/2
= x^(1 + 1/2)
= x^3/2
So the derivative of 3x^3/2 is found as follows:
y' = 3 * 3/2x^(3/2 - 1)
= (9/2)x^1/2
= (9/2)√x.
The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant =
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.