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SVEN [57.7K]
3 years ago
9

Which number is irrational?? Help..!

Mathematics
1 answer:
kakasveta [241]3 years ago
5 0
B is the irrational. C & D are rational as they can be written in a ratio, aka a simple fraction. A is rational as it simplifies to +/-2, a whole number.
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What is the area of the Red Cross-section??? PLEASE HELP!!!!
alexandr1967 [171]
X is the radius of the slice.  So we must find the equation of the side of the cone.

y=mx+b, so now we must use two points to solve for the slope, or "m".

m=(y2-y1)/(x2-x1)

m=(0-15)/(5-0)

m=-15/5

m=-3  so our line so far is:

y=-3x+b, b=y-intercept=value of y when x=0, which we can see is 15 ft so:

y=-3x+15

Now the radius is x, so we must solve for x from the equation above...

-3x+15=y  subtract 15 from both sides

-3x=y-15  divide both sides by -3

x=(15-y)/3

And area of this circle is:

A=πx^2, and using x found above:

A=(π/9)(15-y)^2

A=(π/9)(225-30y+y^2), so when y=6 ft

A=(π/9)(225-30*6+6^2)

A=(π/9)(81)

A=9π or if we let π=pi

A=9pi ft^2
8 0
3 years ago
Please help me fast .!!!
zhannawk [14.2K]

Answer:

it would be 5,4                                                  

Step-by-step explanation:

go to 5 the to 4 wich would then lead you to 5,4

5 0
3 years ago
Which of the following is a valid exclusion for the algebraic fraction 8ab^2x/4a^2b-8ab^2
Molodets [167]

Answer:

a ≠ 2b

Step-by-step explanation:

The given expression is

\frac{8ab^{2}x}{4a^{2}b-8ab^{2}}

=\frac{8ab^{2}x}{4ab(a-2b)}

Simplifying it, we have

\frac{8ab^{2}x}{4a^{2}b-8ab^{2}} = \frac{bx}{a-2b}

For the above fraction to exist, the denominator must not be equal to zero.

i.e, a-2b ≠ 0

=> a≠2b

∴ The algebraic fraction exists when a≠2b.


3 0
3 years ago
Read 2 more answers
4th out of 10 questions
lisabon 2012 [21]

(9, 15) since when you multiply them by 3 both values are equivalent.

6 0
3 years ago
Factor and Solve. Show work.
Naddik [55]

Step-by-step explanation:

1. We we can split 4p into 9p - 5p, and now we have 3p² + 9p - 5p - 15 = 0. We can take out 3p from the first 2 terms and -5 from the last 2 terms. This gets us 3p (p + 3) -5 (p + 3) = 0. These two terms have (p + 3) as a common facor, so we can take that out as well, which give us (p + 3)(3p - 5) = ). Using Zero Product Property, p + 3 = 0 and 3p - 5 = 0, and when we solve each equation, we get p = -3, p= 5/3.

2. We will use the same process.

6x² + 14x - 3x - 7 = 0

2x (3x+7) - 1 (3x+7) = 0

(3x + 7)(2x - 1) = 0

3x + 7 = 0, 2x - 1 = 0

x = -7/3, x=1/2

Hope this helps!

4 0
3 years ago
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