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pickupchik [31]
3 years ago
13

HELP PLEASE ASAP!!! 50 points

Mathematics
2 answers:
neonofarm [45]3 years ago
3 0

Answer:

(a+b,c)

Step-by-step explanation:

Note that the midpoint formula is:

(\frac{x_{1} +x_{2}}{2}, \frac{y_{1} +y_{2}}{2})

Point A (0,0) and Point C (2a+2b,2c)

It follows that:

(\frac{(2a+2b +0}{2}, \frac{2c+0}{2})\\(\frac{(2(a+b)}{2}, \frac{2c}{2})\\\\(a+b,c)


Tom [10]3 years ago
3 0

\text{The formula of a midpoint:}\\\\\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)\\\\\text{We have}\ A(0,\ 0)\ \text{and}\ C(2a+2b,\ 2c).\\\\\text{Substitute:}\\\\x=\dfrac{0+2a+2b}{2}=\dfrac{2a}{2}+\dfrac{2b}{2}=a+b\\\\y=\dfrac{0+2c}{2}=\dfrac{2c}{2}=c\\\\Answer:\ \boxed{c.\ (a+b,\ c)}

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