Answer:
It will take 3 hours. They will both have completed 11 rows.
Step-by-step explanation:
1 row of carrots per hour = frank
3 rows of tomatoes per hour = frank's mom
right now, this is how many they have completed
frank - 8 rows
mom - 2 rows
1st hour
f - 9
m - 5
2nd hour
f - 10
m - 8
3rd hour
f - 11
m - 11
Answer:
The answers to each part are:
Part A.
- <u>The quantity of apples is one-third of the quantity of grapes</u>.
Part B.
- <u>The quantity of apples is a quarter of the quantity of strawberries</u>.
Part C.
- <u>The number of cherries is two-elevenths of the total fruit</u>.
Step-by-step explanation:
To identify the answer in each case, you must remember that all the parts are equal, then:
Part A.
The parts of apples are 1 and the parts grapes are 3, so if you divide the first quantity with the second quantity you obtain:
So, <u>the quantity of apples is one-third of the quantity of grapes</u> or the quantity of apples is three times smaller than the quantity of grapes.
Part B.
The parts of apples are 1 and the parts of strawberries are 4, then you must divide the first quantity with the second quantity:
In this case, <u>the quantity of apples is a quarter of the quantity of strawberries</u> or the quantity of apples is four times smaller than the quantity of strawberries.
Part C.
First, you must add all the part of fruit:
- <em>1 part apple</em>
- <em>1 part orange</em>
- <em>4 parts strawberry</em>
- <em>2 parts cherry </em>
- <em>3 parts grape</em>
The total of fruits is 11 parts, taking into account the quantity of cherries is 2, now you can divide the number of cherries with the total parts of fruit:
- 2 / 11 = 2/11 (two-elevenths)
Now, you can see <u>the number of cherries is two-elevenths of the total fruit</u>.
Answer:
See the proof below
Step-by-step explanation:
For this case we need to proof the following identity:

We need to begin with the definition of tangent:

So we can replace into our formula and we got:
(1)
We have the following identities useful for this case:


If we apply the identities into our equation (1) we got:
(2)
Now we can divide the numerator and denominato from expression (2) by
and we got this:

And simplifying we got:

And this identity is satisfied for all:

Answer:
x = 18.46
Step-by-step explanation:
Find the last angle of the triangle.
180-90-72 = 18
The cosine of an angle is equal to the ratio of the adjacent side to the hypotenuse.
cos(b) = adj/hyp
CosB=a/c rewrite to get
6/CosB (72) = 19.41
Find the last side of the triangle using the Pythagorean theorem.
b=square root c^2 - a^2
b=square root 376.99 - 36
b= 18.46
Your answer would be A hope this helps!