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4 years ago

What is 4x+3y= -5 and -3x+4y=12 in elimination?

Mathematics

2 answers:

Aleonysh [2.5K]4 years ago

8 0

Answer:

Step-by-step explanation:

4x+3y=-5 ...(1)

-3x+4y=12 ....(2)

By 3(1)+4(2) gives

12 x+9y-12x+16y=-15+48

25y=33

y=33/25=1.32

from (1)

4x+3(33/25)=-5

4x=-5-99/25=(-125-99)/25=-224/25

x=-224/100=-2.24

andriy [413]4 years ago

3 0

4x+3y=-5 answer 4x+34+5=0 -3x+4y=12 answer 3x-4y+12=0

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Please help me i need this grade !

lutik1710 [3]

A . One solution

B . infinite solution

C . infinite solution

D . no solution

_________________________________

Thus the correct answer is option A .

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3 years ago

A sequence can be generated by using an = an-1 + 4, where a1 = 6 and n is a whole number greater than 1. What are the first four

Firlakuza [10]

Answer:

The first four terms are 4,8,12,16

Step-by-Step Explanation:

The given relation between the nth term and it's previous term is given by:

$\boxed{an = an - 1 + 4}$

GiveN:

a1 = 4

Now finding the other three terms of the AP with the given relation.

$a2 = a1 + 4$

Putting a1 = 4,

$a2 = 4 + 4 = 8$

Now, Third term:

$a3 = a2 + 4$

Putting a2 = 8,

$a3 = 8 + 4 = 12$

Now, Fourth term:

$a4 = a3 + 4$

Putting a3 = 12,

$a4 = 12 + 4 = 16$

Hence, The first four terms of the AP is 4, 8, 12 & 16.

7 0

3 years ago

Please help with this question! i'm really struggling :(

Dmitriy789 [7]

Answer:

Step-by-step explanation:

You need to learn about Interpreting graphs,x-intercepts and y-intercepts And Translating functions

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3 years ago

A textbook store sold a combined total of 438 biology and psychology textbooks in a week. The number of psychology textbooks sol

Liono4ka [1.6K]

<h2>Answer:</h2>

Number of biology textbooks sold: 257 textbooks

Number of psychology textbooks sold: 181 textbooks

<h2>Explanations:</h2>

Let the total number of biology textbook sold be "a"

Let the total number of psychology textbook sold be "b"

If a textbook store sold a combined total of 438 biology and psychology textbooks in a week, then:

a + b = 438 ................... 1

If the number of psychology textbooks sold was 76 less than the number of biology textbooks sold, then;

b = a - 76 ...................... 2

Substitute equation 2 into 1

a + (a-76) = 438

a + a - 76 = 438

2a = 438 + 76

2a = 514

a = 514/2

a = 257 biology textbooks

From equation 2;

b = a - 76

b = 257 - 76

b = 181 psychology textbooks

Number of biology textbooks sold: 257 textbooks

Number of psychology textbooks sold: 181 textbooks

7 0

1 year ago

Suppose I ask you to pick any four cards at random from a deck of 52, without replacement, and bet you one dollar that at least

Tatiana [17]

Answer:

a) No, because you have only 33.8% of chances of winning the bet.

b) No, because you have only 44.7% of chances of winning the bet.

Step-by-step explanation:

a) Of the total amount of cards (n=52 cards) there are 12 face cards (3 face cards: Jack, Queen, or King for everyone of the 4 suits: clubs, diamonds, hearts and spades).

The probabiility of losing this bet is the sum of:

- The probability of having a face card in the first turn

- The probability of having a face card in the second turn, having a non-face card in the first turn.

- The probability of having a face card in the third turn, having a non-face card in the previous turns.

- The probability of having a face card in the fourth turn, having a non-face card in the previous turns.

1) The probability of having a face card in the first turn

In this case, the chances are 12 in 52:

$P_1=P(face\, card)=12/52=0.231$

2) The probability of having a face card in the second turn, having a non-face card in the first turn.

In this case, first we have to get a non-face card (there are 40 in the dech of 52), and then, with the rest of the cards (there are 51 left now), getting a face card:

$P_2=P(non\,face\,card)*P(face\,card)=(40/52)*(12/51)=0.769*0.235=0.181$

3) The probability of having a face card in the third turn, having a non-face card in the first and second turn.

In this case, first we have to get two consecutive non-face card, and then, with the rest of the cards, getting a face card:

$P_3=(40/52)*(39/51)*(12/50)\\\\P_3=0.769*0.765*0.240=0.141$

4) The probability of having a face card in the fourth turn, having a non-face card in the previous turns.

In this case, first we have to get three consecutive non-face card, and then, with the rest of the cards, getting a face card:

$P_4=(40/52)*(39/51)*(38/50)*(12/49)\\\\P_4=0.769*0.765*0.76*0.245=0.109$

With these four probabilities we can calculate the probability of losing this bet:

$P=P_1+P_2+P_3+P_4=0.231+0.181+0.141+0.109=0.662$

The probability of losing is 66.2%, which is the same as saying you have (1-0.662)=0.338 or 33.8% of winning chances. Losing is more probable than winning, so you should not take the bet.

b) If the bet involves 3 cards, the only difference with a) is that there is no probability of getting the face card in the fourth turn.

We can calculate the probability of losing as the sum of the first probabilities already calculated:

$P=P_1+P_2+P_3=0.231+0.181+0.141=0.553$

There is 55.3% of losing (or 44.7% of winning), so it is still not convenient to bet.

5 0

4 years ago