Solve -x^2 + 4x +10 = 0 by using the "Solving the square method"

Mathematics

1 answer:

Pavel [41]2 years ago

3 0

Answer:

$x = - 2 + \sqrt{14} \: \: or \: \: x = - 2 - \sqrt{14}$

Step-by-step explanation:

${x}^{2} - 4x - 10 = 0 \\ {x}^{2} - 4x = 10 \\ {x}^{2} - 2(2x) = 10 \\ {x }^{2} - 2(2x) + 4 = 10 + 4 \\ {(x + 2)}^{2} = 14 \\ x + 2 = \sqrt{14} \: \: \: \: or \: \: \: x + 2 = - \sqrt{14}$

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What is the equation of the line that is parallel to the

erastovalidia [21]

Answer:

Step-by-step explanation:

A parallel line will have the same slope as the reference line. In this case, I don't see the "given line" as promised in the question. If it does appear, and it looks like y = 5x + 3, for example, the slope is 5 and the new line will have the same slope.

<h3><u>If this slope is correct</u>, we can start the equation for the parallel line that goes through point (-3,2) by starting with:</h3><h3 /><h3>y = 5x + b</h3><h3 /><h3>We need a value of b that forces the line to go through point (-3,2). We can do that by using the given point in the equation and solving for b:</h3><h3>y = 5x + b</h3><h3>2 = 5(-3) + b</h3><h3>b = 17</h3><h3 /><h3>The parallel line to y=5x+3 is</h3><h3>y = 5x + 17</h3><h3 /><h3>See attachment.</h3><h3 /><h3 /><h3 />