3 years ago

A rectangular garden is fenced on all sides with 278 feet of fencing. The garden is 9 feet longer than it is

Mathematics

1 answer:

JulijaS [17]3 years ago

6 0

It’s 301 bc u add them together

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Harman [31]

Answer:

i have no idea but if i had to guess it would be around -3.00k or -4.00k

Step-by-step explanation:

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3 years ago

a triangle pyramid has lateral faces with bases of 6meters and hights of 9 meters the area of the base of the pyramid

Alexxandr [17]

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Solve for x:<br> I need a answer with an explanation. Algebra 1

kirill115 [55]

Answer: x = -1

Step-by-step explanation:

You need to convert to the same base

$\frac{1}{16} = \frac{1}{2^{4} } = 2^{-4}$

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3 years ago

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Fudgin [204]

Answer and workings in the attachment below.

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4 years ago

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andrew11 [14]

Use the distance formula.

$\sqrt{( x_{2} - x_{1} )^2 + (y_{2} - y_{1})^2}$

Points S and W.
$\sqrt{(3)^2 + (2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points S and T
$\sqrt{(3 - 0)^2 + (-2 - 0)^2}$

$\sqrt{(3)^2 + (-2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points T and U
$\sqrt{(3 - 2)^2 + (-2 + 5)^2}$

$\sqrt{(1)^2 + (3)^2}$

$\sqrt{1+9}$

$\sqrt{10}$

~3.1

Points U and V
$\sqrt{(2+2)^2 + (-5 + 5)^2}$

$\sqrt{(4)^2 + (0)^2}$

$\sqrt{16}$

~4

Points V and W
$\sqrt{(-2+3)^2 + (-5 + 2)^2}$

$\sqrt{(1)^2 + (-3)^2}$

$\sqrt{2+9}$

$\sqrt{11}$

~3.3

Add all these together.

3.3 + 3.1 + 4 + 3.1 + 3.6
≈17

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4 years ago