What is the potential energy of a spring that is compressed 0.65 m by a 25 kg block if the spring constant is 95 N/m?For which e
1 answer:
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Answer: The vapor pressure of water at 298 K is 3.565kPa.
Explanation:
The vapor pressure is determined by Clausius Clapeyron equation:
where,
= initial pressure at 298 K = ?
= final pressure at 373 K = 101.3 kPa
= enthalpy of vaporisation = 41.1 kJ/mol = 41100 J/mol
R = gas constant = 8.314 J/mole.K
= initial temperature = 298 K
= final temperature = 373 K
Now put all the given values in this formula, we get
Therefore, the vapor pressure of water at 298 K is 3.565kPa.