Answer:
Atomic mass of nitrogen = 14.0067 amu.
Explanation:
Isotopes can be defined as two or more forms of a chemical element that are made up of equal numbers of protons and electrons but different numbers of neutrons.
Generally, the isotopes of a chemical element have the same chemical properties because of their atomic number but different physical properties due to their atomic weight (mass number).
The two isotopes of nitrogen are nitrogen-14 and nitrogen-15.
Given the following data;
Relative abundance of N-14 = 99.63%
Atomic mass of N-14 = 14.003
Relative abundance of N-15 = 0.37%
Atomic mass of N-15 = 15.000
The atomic mass is;
14.003 × (99.63/100) + 15.000 × (0.37/100)
Atomic mass = 14.003 × (0.9963) + 15.000 × (0.0037)
Atomic mass = 13.9512 + 0.0555
Atomic mass = 14.0067 amu.
<em>Therefore, the atomic mass of nitrogen is 14.0067 amu. </em>
Answer:
gold wire (Au)
Explanation:
A substance that cannot be separated or broken down into simpler substances by chemical means is an element.
Between the given options only gold wire is an element, Au.
A way of knowing that it is an element is noticing that its formula is a single symbol which corresponds to an element found in the periodic table, unlike a combination of said symbols (like NaCl or H₂O).
Answer:
did you ever get the answer lol
Answer:
3NaOH (aq) + Fe(NO₃)₃ (aq) → Fe(OH)₃ (s) + 3NaNO₃ (aq)
Explanation:
Step 1: RxN
NaOH (aq) + Fe(NO₃)₃ (aq) → Fe(OH)₃ (s) + NaNO₃ (aq)
Step 2: Balance RxN
We need 3 OH's on both sides.
We also need 3 NO₃'s on both side.
- This will make it so we also need 3 Na's on both side
3NaOH (aq) + Fe(NO₃)₃ (aq) → Fe(OH)₃ (s) + 3NaNO₃ (aq)
Answer:
Regarding Measures of center, the Mean will be smaller, and Median will not be affected. Thus, the median will not change, since the temperature was already low initially and only decreased. However, the median takes the average of all values into account, and if you substitute a value for a smaller value, the average decreases.
In relation to Measures of spread, the range and standard deviation will be larger, and the IQR will not change. Therefore, the range is the highest minus the lowest number; if the lowest number decreases sharply, the range increases. On the other hand, the IQR only counts the first and third quartile values. Therefore, since the value was already the lowest, if it is decreased, it will not change the IQR. However, the standard deviation will increase significantly, as the decreasing value of the lowest data point will increase the overall spread.
Explanation:
