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2 years ago

14

Use the patterns you identified to estimate the likely melting point for potassium (K) in Group 1 and barium (Ba) in Group 2. En

ter your estimate in the figure. Explain your reasoning

1 answer:

posledela2 years ago

7 0

The melting point for potassium (K) is 63.5 °C whereas melting point of barium (Ba) is 727 °C.

<h3>Reason for high melting point</h3>

The melting point of barium is higher than potassium because of the presence of metallic bonding in the giant structure of a barium metal is very strong. These metallic bonds requires large amounts of energy for breaking.

While on the other hand, potassium has large atomic size than barium so the melting of potassium is lower than barium so we can conclude that melting point of potassium is lower than barium atom.

Learn more about melting point here: brainly.com/question/40140

Learn more: brainly.com/question/26195266

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Answer:

130ml of HCl(36%) in 4.90L solution => pH = 1.50

Explanation:

Need 4.90L of HCl(aq) solution with pH = 1.5.

Given pH = 1.5 => [H⁺] = 10⁻¹·⁵M = 0.032M in H⁺

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12M·V(conc) = 0.032M·4.91L

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3 years ago

Will a parachute slow a skydiver more at a very high altitude or a lower altitude?

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The answer is High altitude

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3 years ago

A mole of oxygen and a mole of hydrogen (at STP) have all of the following in common EXCEPT

Drupady [299]

Answer:

Root mean squared velocity is different.

Explanation:

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In this case, since we have a mixture of oxygen and nitrogen at STP, which is defined as a condition whereas T = 298 K and P = 1 atm, we can infer that these gases have the same temperature, pressure, volume and moles but a different root mean squared velocity according to the following formula:

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2 years ago

A chemist fills a reaction vessel with 9.20 atm nitrogen monoxide (NO) gas, 9.15 atm chlorine (CI) gas, and 7.70 atm nitrosyl ch

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Answer:

The reactions free energy $\Delta G = -49.36 kJ$

Explanation:

From the question we are told that

The pressure of (NO) is $P_{NO} = 9.20 \ atm$

The pressure of (Cl) gas is $P_{Cl} = 9.15 \ atm$

The pressure of nitrosly chloride (NOCl) is $P_{(NOCl)} = 7.70 \ atm$

The reaction is

$2NO_{(g)} + Cl_2 (g)$ ⇆ $2 NOCl_{(g)}$

From the reaction we can mathematically evaluate the $\Delta G^o$ (Standard state free energy ) as

$\Delta G^o = 2 \Delta G^o _{NOCl} - \Delta G^o _{Cl_2} - 2 \Delta G^o _{NO}$

The Standard state free energy for NO is constant with a value

$\Delta G^o _{NO} = 86.55 kJ/mol$

The Standard state free energy for $Cl_2$ is constant with a value

$\Delta G^o _{Cl_2} = 0kJ/mol$

The Standard state free energy for $NOCl$ is constant with a value

$\Delta G^o _{NOCl} =66.1kJ/mol$

Now substituting this into the equation

$\Delta G^o = 2 * 66.1 - 0 - 2 * 87.6$

$= -43 kJ/mol$

The pressure constant is evaluated as

$Q = \frac{Pressure \ of \ product }{ Pressure \ of \ reactant }$

Substituting values

$Q = \frac{(7.7)^2 }{(9.2)^2 (9.15) } = \frac{59.29}{774.456}$

$= 0.0765$

The free energy for this reaction is evaluated as

$\Delta G = \Delta G^o + RT ln Q$

Where R is gas constant with a value of $R = 8.314 J / K \cdot mol$

T is temperature in K with a given value of $T = 25+273 = 298 K$

Substituting value

$\Delta G = -43 *10^{3} + 8.314 *298 * ln [0.0765]$

$= -43-6.36$

$\Delta G = -49.36 kJ$

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Answer:

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