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Vinil7 [7]
3 years ago
7

Calculate the mass in grams of a single atom C¹²​

Chemistry
2 answers:
WARRIOR [948]3 years ago
7 0

Answer: c12 has a mass of 12 amu

Explanation:

mass of one mole of c12 = g. So mass of 1 atom of c12 = 1.9927e-23g

Alexxx [7]3 years ago
3 0
C12 has a mass of 12amu
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A car driving east along the freeway at 60 m/s hits some traffic and after 7 seconds is
Vladimir79 [104]
Do u know how to solve area
4 0
3 years ago
Find the empirical formula of the following compound: 0.77 mol of iron atoms combined with 1.0 mol of oxygen atoms.
eimsori [14]

The empirical formula is Fe₃O₄.

The empirical formula is the <em>simplest whole-number ratio of atoms</em> in a compound.

The ratio of atoms is the same as the ratio of moles, so our job is to calculate the molar ratio of Fe to O.

I like to summarize the calculations in a table.

<u>Element</u>   <u>Moles</u>    <u>Ratio</u>¹   <u>×3</u>²   <u>Integers</u>³

    Fe         0.77       1         3             3

    O           1.0         1.3      3.9          4

¹ To get the molar ratio, you divide each number of moles by the smallest number (0.77).

² If the ratio is not close to an integer, multiply by a number (in this case, 3) to get numbers that are close to integers.

³ Round off these numbers to integers (3 and 4).

The empirical formula is Fe₃O₄.

7 0
3 years ago
The air pressure in a tire is 2.38 atm. What is the pressure in kilopascals.
Anna71 [15]

Answer:

The answer is

<h2>241.15 kPa</h2>

Explanation:

To find the pressure in kilopascals we must first find the pressure in Pascal

To find the pressure in Pascal we use the conversion

1 atm = 101 , 325 Pa

If 1 atm = 101325 Pa

then 2.38 atm = 2.38 × 101325

= 241153.5 Pa

Converting it into kPa we have the final answer as

<h3>241.15 kPa</h3>

Hope this helps you

8 0
3 years ago
Imagine if Rutherford conducted his scattering experiment, and his prediction about the movement of alpha particles held true Wh
IRINA_888 [86]

Answer:

The plum pudding model would have to be true as well because it shows that electrons are scattered within an atom.

Explanation:

I took the test and got it right :)

4 0
3 years ago
Calcium has a cubic closest packed structure (fcc) as a solid. Assuming that calcium has an atomic radius of 197 pm, calculate t
Paha777 [63]

Answer:

1.536 g/cm^3 is the density of solid calcium.

Explanation:

Formula used :  

\rho=\frac{Z\times M}{N_{A}\times a^{3}}

where,

\rho = density

Z = number of atom in unit cell

M = atomic mass

(N_{A}) = Avogadro's number  

a = edge length of unit cell

We have:

r = 197 pm = 197\times 10^{-12} m = 197\times 10^{-12}\times 100 cm

r=197\times 10^{-10} m

a=r\times 2\sqrt{2}

a=197\times 10^{-10} m\times 2\sqrt{2}=557.200\times 10^{-10} cm

M = 40 g/mol

Z = 4

On substituting all the given values , we will get the value of 'a'.

\rho =\frac{4\times 40 g/mol}{6.022\times 10^{23} mol^{-1}\times (557.200\times 10^{-10} cm)^{3}}

\rho =1.536 g/cm^3

1.536 g/cm^3 is the density of solid calcium.

5 0
3 years ago
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