yes I doso u need to find the amount of grams total and the individual amount of grams.so 40+40+52+16+16+16+16=196g (I got the numbers from the periodic table)K- 80gCr-52gO-64gsince you are solving for oxygen, you would only use the oxygen part so...64g/196g=32.9%32.9% is the answer hope this helps! if it doesn't, let me know in the comments! have a blessed day!
Concepts to understand before solving:
-Oxygen is ALWAYS reduced
-OIL- Oxidation Is Loss of electrons
-RIG- Reduction Is Gain of electrons
-the element that is oxidized is the reducing agent
-the element that is reduced is the oxidizing agent
A. 2H2 + O2 —> 2H2O
O is reduced, making it the oxidizing agent
H is oxidized, making it the reducing agent
B. 2KNO3 —> 2KNO2 + O2
O is reduced, making it the oxidizing agent
KNO is oxidized, making it the reducing agent
Answer:
Overall reaction equation;
2NO(g) +Cl2(g) -----> 2NOCl (g)
Explanation:
Given
1) NO(g) + Cl2(g) → NOCl2(g)
2) NOCl2(g) + NO(g) → 2NOCl(g)
Overall reaction equation;
2NO(g) +Cl2(g) -----> 2NOCl (g)
k1= [NOCl2]
k-1= [NO] [Cl2]
k2 = [NOCl2] [NO]
Equilibrium for the first equation (reaction 1)
K= k1/k-1 = [NOCl2]/[NO] [Cl2]
Therefore
[NOCl2] = k1/k-1 [NO] [Cl2]
Rate= k2× k1/k-1 [NO]^2 [Cl2]
Rate = Koverall [NO]^2 [Cl2]
Where Koverall= k1k2/k-1
