Answer:
0.1 = 10% probability that the class length is between 51.5 and 51.7 min, that is, P(51.5 < X < 51.7) = 0.1.
Step-by-step explanation:
A distribution is called uniform if each outcome has the same probability of happening.
The uniform distributon has two bounds, a and b, and the probability of finding a value between c and d is given by:

The lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min.
This means that 
If one such class is randomly selected, find the probability that the class length is between 51.5 and 51.7 min.

0.1 = 10% probability that the class length is between 51.5 and 51.7 min, that is, P(51.5 < X < 51.7) = 0.1.
Answer:
13.22
Step-by-step explanation:
were solving for t and we know:
a(t)=p(1+(r/n))^nt
5000=a-the total
2940=p-the starting amount
.041=r-the rate
1=n-compound (annual)
plug this into a graph :
5000=2940(1+(.041/1))^x
and you get : 13.22
Answer:
A
Step-by-step explanation:
This notation says that x+x+x+x+37=69
This can be simplified to say 4x+37=69
10% of 4200 is 420
2% of 4200 is 84
420+84 is 504
4200-504=3696
Hope this helps