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ss7ja [257]
4 years ago
8

Find the value of p= 3a + 4b - 6c when a=2 b=3 and c=-1

Mathematics
2 answers:
NARA [144]4 years ago
7 0
Simply make the substitution.

P = 3a + 4b -6c                a=2, b=3, c=-1.

P = 3*(2) + 4*(3) - 6*(-1)          Multiply out.

P = 6 +12 +6 = 24.

P = 24.

Happy exams.
ololo11 [35]4 years ago
6 0
Oh this is easy! Basically you use substitution - so you put in the numbers into the letters:

P = 3a + 4b -6c a = 2 b = 3 and c = -1
(PUT NUMBERS INTO LETTERS)
P = 3(2) + 4(3) - 6(-1)
P = (3x2) + (4x3) -(6x-1)
P = 6 + 12 + 6
P = 24
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6 0
1 year ago
Colby and jaquan are growing bacteria in an experiment in a laboratory. Colby starts with 50 bacteria in his culture and the num
Oksanka [162]

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2) y = 80 * 2⁸ˣ

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Colby's experiment:

y = 50 * 2¹²ˣ

Jaquan's experiment:

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5 0
3 years ago
Which of the following describes the translation of the graph of y = x2 to obtain the graph of y = -x2 - 3?
Ray Of Light [21]

Answer:

reflections across the x axis and a shift down 3 units

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5 0
3 years ago
The sum of four consecutive integers is 342. What is the third term in the sequence
Fofino [41]

Answer:

86

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4n + 6 = 342

4n + 6  - 6  = 342 - 6

4n = 336

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4 0
3 years ago
Determine which consecutive integers do not have real zeros between them.
Alisiya [41]
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 Below is a graph of the function.

5 0
3 years ago
Read 2 more answers
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