Answer:
246 ft is the maximum height
Step-by-step explanation:
The height h given above is a quadratic function. The graph of h as a function of time t gives a parabolic shape and the maximum height h occur at the vertex of the parabola. For a quadratic function of the form h = a t² + bt + c, the vertex is located at t = - b / 2a. Hence for h given above the vertex in the question s(t) = 124 + 64t − 16t², is at t
t = -64/2(-16) = 64/32 = 2 seconds
Thus, 2 seconds after the object was thrown, it reaches its highest point (maximum value of h) which is given by
h = -16(2)² + 64 (2) + 124 = 246eet
<h3><u>given</u><u>:</u></h3>
base= 25mm
height= 28mm
<h3><u>to</u><u> </u><u>find</u><u>:</u></h3>
the volume of the pyramid.
<h3><u>solution</u><u>:</u></h3>
v= a^2 h/3
v= 25^2 28/3
v= 5833.33333
v= 5833.3mm^3
Your inequality has one solution which is p = 1/4
Answer:
Equation of circle in standard form with centre (0, – 10) and radius 6. 
Step-by-step explanation:
We need to write equation of circle in standard form with centre (0, – 10) and radius 6.
The equation of circle is: 
where (h,k) is centre of circle and r is radius
We are given centre (0,-10) so, h=0, k=-10 and radius r = 6
Putting values and finding equation:
So, equation of circle in standard form with centre (0, – 10) and radius 6.
Answer:
1st option is the answer
Step-by-step explanation:
blue line: slope is 1 and y-intercept is 1; therefore equation is y= x + 1
red line: slope is -1 and y-intercept is -3; therefore equation is y= -x - 3
