Question

Find the inverse of each given functions h(x)=2x-4/3

Answer 1

Answer:

$h(x')=\frac{x}{2} +\frac{2}{3}$

Step-by-step explanation:

We are given the following function:

$h(x)=2x-\frac{4}{3}$

To find the inverse of this function, we will put this function equal to y (another variable) and then make x the subject of it.

$y=2x-\frac{4}{3}$

$y+\frac{4}{3} =2x$

$\frac{y}{2} +\frac{4}{6} =x$

$x=\frac{y}{2} +\frac{2}{3}$

Now changing back the variable y to x to make it the inverse of h(x) to get:

$h(x')=\frac{x}{2} +\frac{2}{3}$

Therefore, the inverse of the given function h(x) is $h(x')=\frac{x}{2} +\frac{2}{3}$.

Answer 2

Answer:

h^-1(x) = (3x+4)/2

answer choice c