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Sveta_85 [38]
3 years ago
13

Find the slope of the line that passes through each pair of points.

Mathematics
1 answer:
e-lub [12.9K]3 years ago
8 0

Answer:

<u>0.5</u>

Step-by-step explanation:

Slope (m) =  

ΔY

ΔX

=  

1

2

= 0.5

θ =  

arctan( ΔY ) + 180°

ΔX

= 206.56505117708°

ΔX = 0 – 2 = -2

ΔY = 0 – 1 = -1

Distance (d) = √ΔX2 + ΔY2 = √5 = 2.2360679774998

Equation of the line:

y = 0.5x

When x=0, y = 0

When y=0, x = -0

BRAINIEST PLEASE??

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3 years ago
If m&lt;ECD is six less than five times m&lt;BCE. and m&lt;BCD = 162°, find each measure.(Sorry bout using the wrong signs, but
tia_tia [17]

Answer:

m∠BCE = 28° and m∠ECD = 134°

Step-by-step explanation:

* Lets explain how to solve the problem

- The figure has three angles: ∠BCE , ∠ECD , and ∠BCD

- m∠ECD is six less than five times m∠BCE

- That means when we multiply measure of angle BCE by five and

 then subtract six from this product the answer will be the measure

 of angle ECD

∴ m∠ECD = 5 m∠BCE - 6 ⇒ (1)

∵ m∠BCD = m∠BCE + m∠ECD

∵ m∠BCD = 162°

∴ m∠BCE + m∠ECD = 162 ⇒ (2)

- Substitute equation (1) in equation (2) to replace angle ECD by

  angle BCE

∴ m∠BCE + (5 m∠BCE - 6) = 162

- Add the like terms

∴ 6 m∠BCE - 6 = 162

- Add 6 to both sides

∴ 6 m∠BCE = 168

- Divide both sides by 6

∴ m∠BCE = 28°

- Substitute the measure of angle BCE in equation (1) to find the

  measure of angle ECD

∵ m∠ECD = 5 m∠BCE - 6

∵ m∠BCE = 28°

∴ m∠ECD = 5(28) - 6 = 140 - 6 = 134°

* m∠BCE = 28° and m∠ECD = 134°

3 0
3 years ago
Read 2 more answers
Help me!!!!!!!!!!!!!
irakobra [83]
Seven twenty-two am 
7:22am
8 0
3 years ago
Read 2 more answers
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