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emmainna [20.7K]
4 years ago
12

Use PEMDAS to simplify the following expression:

Mathematics
2 answers:
Verdich [7]4 years ago
7 0
The answer will be 16 because you multiply then add

sashaice [31]4 years ago
7 0
Ok so, the "P" stands for parentheses, the "E" stands for exponents, orn^{n}. the "M" stands for multiplication, the "d" means you divide, the "a" means you add, and the "s" means you subtract. So, for question number 5, you would do  2x6 because there is no exponents or parentheses, so 2x6=12. Then you would add the 12 and the 4 together, so 12+4=16. Your answer is 16. 
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How do you solve this question? Any help appreciated!
fiasKO [112]
\bf \displaystyle \int\limits_{1}^{e}\cfrac{1}{t}\cdot dt\\\\
-------------------------------\\\\
\textit{doing substitution}\\\\
u=\cfrac{1}{t}\implies u=t^{-1}\implies \cfrac{du}{dt}=-t^{-2}\implies \cfrac{du}{dt}=-\cfrac{1}{t^2}\\\\\\ -t^2du=dt\\\\
-------------------------------\\\\
\displaystyle \int\limits_{1}^{e}u\cdot -t^2du\impliedby \textit{now, let's do some substitution on the "t"}\\\\
-------------------------------\\\\

\bf u=\cfrac{1}{t}\implies t=\cfrac{1}{u}\implies t^2=\cfrac{1^2}{u^2}\implies t^2=\cfrac{1}{u^2}\\\\
-------------------------------\\\\
\displaystyle \int\limits_{1}^{e}u\cdot -\cfrac{1}{u^2}\cdot du\implies -1\int\limits_{1}^{e}\cfrac{1}{u}\cdot du\implies \left. -ln|u| \cfrac{}{}\right]_1^e

\bf \left. -ln\left( \frac{1}{t} \right) \cfrac{}{}\right]_1^e\implies 
\left[ -ln\left( \frac{1}{e} \right) \right]-\left[ -ln\left( \frac{1}{1} \right) \right]\implies 
\left[ -ln\left( e^{-1}\right) \right]-\left[ -ln\left( 1\right) \right]
\\\\\\\
[-(-1)]-[-(0)]\implies 1-0\implies 1
8 0
3 years ago
PLEASE HELP!!!!!! the sum of a number times 10 and 15 is at most -17
Brilliant_brown [7]

Let the number = x

Writing the equation you have:

10x + 15 <= -17

Solve for x

Subtract 15 from both sides:

10x <= -32

Divide both sides by 10:

X <= -32/10

Simplify:

X <= -16/5 as a fraction or -3.2 as a decimal

3 0
4 years ago
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