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Yakvenalex [24]
3 years ago
6

Solve 3x2 – 18x + 5 = 47 for x.

Mathematics
2 answers:
velikii [3]3 years ago
5 0

Answer:

x = 3 +√23 and x = 3 - √23

Step-by-step explanation:

The given equation 3x^2 -18x +5 = 47

This can be written as 3x^2 -18x + 5 - 47 =0

3x^2 -18x - 42 = 0

Here we have to use the quadratic formula.

x = \frac{-b +/- \sqrt{b^2 - 4ac} }{2a}

From the given equation, a = 3, b = -18 and c = -42

Plug in these values in the above formula, we get

x = \frac{-(-18) +/- \sqrt{(-18)^2 - 4.3.(-42)} }{2.3}

x = \frac{18 +/- \sqrt{828} }{6}

Simplifying the above expression, we get

x = 3 +√23 and x = 3 - √23

Hope this will helpful.

Thank you.

Ivenika [448]3 years ago
5 0

Answer:

x = 3 (+-)√23

ANSWER A

Step-by-step explanation:

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Given equation: A(n - 3) +8= bn.

Solution: On the left side of the equation we have A(n-3).

We don't have any sign in between A and parenthesis (n-3).

So, we need to multiply A and (n-3).

We need to apply distributive property to multiply A and (n-3).

Distributing A over (n-3), we get

A(n-3) = A*n - 3*A = An -3A.

Substituting this value in original equation,

An -3A +8= bn.

We need to solve it for n, so we get n terms on a side.

We have An on left side, we need to get rid n from left side.

Subtracting An from both sides, we get

An -3A +8-An= bn-An.

-3A +8 = bn - An.

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Factoring out n on right side from bn-an.

-3A +8 = (b - A)n.

Dividing both sides by (b-A),

\frac{(-3A+8)}{(b-A)} = \frac{(b-A)n}{(b-A)}

On right (b-A) paranthiss cancelled and we get n on right side.

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