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Darya [45]
2 years ago
8

8. A rectangular prism has a volume of 468 cubic meters. It has a length of 12 meters and a width of 6 meters. What is the heigh

t of the prism? ​
Mathematics
1 answer:
evablogger [386]2 years ago
6 0
Jdjrhfhfhfhfhfjfhfhfjfjfjfjfjfjfjfjfnghg
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The functions s and t are defined as follows.
soldi70 [24.7K]
-77
You first solve for s(x) by plugging in 5 as the variable
-3*5-4=-19
You then plug the -19 into t(x) and 4*-19-1= -77
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3 years ago
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Solve Triangle DEF. - Math
Brrunno [24]

Answer:

p = 52.942259755149776

Step-by-step explanation:

This is basic trigonometry.

\cos(39)  =  \frac{e}{22}

e =  \cos(39)  \times 22

\sin(39)  =  \frac{d}{22}

d =  \sin(39)  \times 22

And finally perimeter (p):

p = 22 +  e+ d

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2 years ago
Express the set in roster form.<br><br>{x|x is an integer greater than -6}
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\{x|x\in\mathbb{Z}\ \wedge\ x > -6\}=\{-5;-4;-3;-2;-1;\ 0;\ 1;\ 2;\ 3;\ 4;\ 5;..\}
7 0
3 years ago
I really need help with these questions:
slava [35]
If we take the Pythagorean identity identity sin^2 x + cos^2 x = 1 then
                          <span>(cos^2 x + sin^2 x) / (cot^2 x - csc^2 x)
The numerator becomes 1 since addition order matters not.
                                                 1 / </span>(cot^2 x - csc^2 x)
If we factor the denominator out a negative
                                                1 / -(<span>csc^2 x - cot^2 x)
Consider </span><span>sin^2 x + cos^2 x = 1. Divide both sides by sin^2 x to get
                                         1 + cot^2 x = csc^2 x
Subtract both sides by cot^2 x to get 1 = csc^2 x - cot^2 x.
Replace the denominator
                                                 1 / -(1) = -1
For cos</span>^2 θ / sin^2 θ + csc θ sin θ, we use cscθ = 1/sinθ and cosθ/sinθ = cotθ so
                                = cos^2 θ / sin^2 θ + 1
                                = cot^2 θ + 1
We use 1 + cot^2 <span>θ = csc^2 </span>θ to simplify this to
                              = csc^2 θ

Answers:         -1
                          csc^2 θ
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3 years ago
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Advocard [28]
What is the question you are trying to ask ?
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