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Reika [66]
2 years ago
5

Mr and Mrs Baker place 12-inch rulers along the length of a rug. They each line up 3 rulers along the edge of the rug. What is t

he length of the rug?
about__feet
Mathematics
2 answers:
kati45 [8]2 years ago
5 0
The length of the rug would be about 36 feet because 12x3=36.
Daniel [21]2 years ago
4 0
3 Feet
12 inches= 1 foot
36 inches = 3 feet
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Evaluate the expression if r = 12 and t = -6.<br> (t-r)/3
Lynna [10]

Answer:

-6

Step-by-step explanation:

\frac{(t-r)}{3}

input the numbers

\frac{(-6-12)}{3}

do the problem in the parentheses first

-6-12 = -18

now it becomes

-\frac{18}{3}

simplify and you'll get

-6

this is because -18 ÷ 3 =

-6

4 0
3 years ago
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Solve the system using a matrix. NEED HELP ASAP!!:):)
icang [17]

1,-4 sorry if wrong :(

7 0
2 years ago
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An object launched vertically from a point that is 37.5 feet above ground level with an initial velocity of 48.6 feet per second
Elis [28]

Answer: 3.675 seconds

Step-by-step explanation:

Hi, when the object hits the ground, h=0:

h=−16t^2+48.6t+37.5

0=−16t^2+48.6t+37.5

We have to apply the quadratic formula:  

For: ax2+ bx + c  

x =[ -b ± √b²-4ac] /2a  

Replacing with the values given:  

a=-16 ; b=48.6; c=37.5

x =[ -(48.6) ± √(-48.6)²-4(-16)37.5] /2(-16)  

x = [ -48.6 ± √ 4,761.96] /-32

x = [ -48.6 ± 69] /-32

Positive:  

x = [ -48.6 + 69] /-32 = -0.6375

Negative:  

x = [ -48.6 - 69] /-32 = 3.675 seconds (seconds can't be negative)

Feel free to ask for more if needed or if you did not understand something.  

8 0
3 years ago
5.146 rounded to the nearest tenth
Gnom [1K]

Answer:

5.1

Step-by-step explanation:

8 0
2 years ago
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The value 5 is an upper bound for the zeros of the function shown below.
Mice21 [21]

Answer:

The given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18  will be true.

Step-by-step explanation:

Given

f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18

We know the rational zeros theorem such as:

if x=c is a zero of the function f(x),

then f(c) = 0.

As the f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18 is a polynomial of degree 4, hence it can not have more than 4 real zeros.

Let us put certain values in the function,

f(5) = 448, f(4) = 126, f(3) = 0, f(2) = -20,

f(1) = 0, f(0) = 18, f(-1) = 16, f(-2) = 0, f(-3) = 0

From the above calculation results, we determined that 4 zeros as

x = -3, -2, 1, and 3.

Hence, we can check that

f(x) = (x+3)(x+2)(x-1)(x-3)

Observe that,

for x > 3, f(x) increases rapidly, so there will be no zeros for x>3.

Therefore, the given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18  will be true.

5 0
3 years ago
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