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vodomira [7]
3 years ago
9

Put them in order from least to greatest: 9.5 9.66 9.662 9.551 9 9.59 9.626

Mathematics
2 answers:
Fiesta28 [93]3 years ago
4 0

Answer:

9, 9.5,9.551,9.59,9.626,9.66,9.662

Step-by-step explanation:

SIZIF [17.4K]3 years ago
3 0
9.662, 9.626, 9.66, 9.59, 9.551, 9.5
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Sergio [31]
Pi IS an: irrational number, a real number

Pi is NOT a: whole number, natural number, rational number, integer
5 0
3 years ago
4 Times the sum of a number and 6 is 5 less than 3 times the same number. write an equation and solve for the number
Vladimir [108]

Answer:

-29

Step-by-step explanation:

4× (x+6) = -5. + 3x

4 times the sum of a number is 5 less than 3 times the same number

4×(x+6) = 3x - 5

4x + 24 = 3x - 5

x = -29

3 0
3 years ago
Please help I need a answer on this question
mestny [16]
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3 0
3 years ago
A, B & C form the vertices of a triangle.
Savatey [412]

Answer:

BC = 17.2.

Step-by-step explanation:

Since CAB = 90º, this is a right triangle.

The triangle format is given below:

C

A           B

We have that AB = 8.6, and angle B measures 60º.

Length of BC:

BC is the hypotenyse.

Side AB is adjacent to angle B = 60º.

In a right triangle, angle \alpha, it's adjacent side with length s and the hypotenuse h are related by the cosine of the angle, that is:

\cos{\alpha} = \frac{s}{h}

In this question, we have an angle of 60º, with has cosine 0.5. We also have that side AB = s = 8.6, and the hypotenuse h is side BC. So

\cos{\alpha} = \frac{s}{h}

0.5 = \frac{8.6}{h}

0.5h = 8.6

h = \frac{8.6}{0.5}

h = 17.2

BC = 17.2.

4 0
3 years ago
All questions to be solved using linear combination.
monitta
1)
I:x-y=-7
II:x+y=7

add both equations together to eliminate y:
x-y+(x+y)=-7+7
2x=0
x=0

insert x=0 into II:
0+y=7
y=7

the solution is (0,7)

2)
I: 3x+y=4
II: 2x+y=5

add I+(-1*II) together to eliminate y:
3x+y+(-2x-y)=4+(-5)
x=-1

insert x=-1 into I:
3*-1+y=4
y=7

the solution is (-1,7)

3)

I: 2e-3f=-9
II: e+3f=18

add both equations together to eliminate f:
2e-3f+(e+3f)=-9+18
3e=9
e=3

insert e=3 into I:
2*3-3f=-9
-3f=-9-6
-3f=-15
3f=15
f=5

the solution is (3,5)

4)
I: 3d-e=7
II: d+e=5

add both equations together to eliminate e:
3d-e+(d+e)=7+5
4d=12
d=3

insert d=3 into II:
3+e=5
e=2

the solution is (3,2)

5)
I: 8x+y=14
II: 3x+y=4

add I+(-1*II) together to eliminate y
8x+y+(-3x-y)=14-4
5x=10
x=2

insert x=2 into II:
3*2+y=4
y=4-6
y=-2

the solution is (2,-2)
8 0
3 years ago
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