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vodomira [7]
3 years ago
9

Put them in order from least to greatest: 9.5 9.66 9.662 9.551 9 9.59 9.626

Mathematics
2 answers:
Fiesta28 [93]3 years ago
4 0

Answer:

9, 9.5,9.551,9.59,9.626,9.66,9.662

Step-by-step explanation:

SIZIF [17.4K]3 years ago
3 0
9.662, 9.626, 9.66, 9.59, 9.551, 9.5
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Answer:

use a calculator

Step-by-step explanation:

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A city’s civil engineer is planning a new parking garage and a new street. The new street will go from the entrance of the parki
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3 0
3 years ago
1 . Solve 4x + 5 > 5x − 2 for x.
Kobotan [32]

I will do number 1 only. You can then use my solution steps to do the rest.

Solve 4x + 5 > 5x − 2 for x.

4x + 5 > 5x − 2

4x - 5x > - 2 - 5

-x > -7

Dividing both sides by a negative number reverses the inequality sign. In other words, the sign > becomes < in the reply.

-x/-1 < -7/-1

x < 7

Answer: x < 7

The answer here means that whatever the value of x is for question 1, it must be less than 7.

You finish.

7 0
3 years ago
Help. please read the instructions and Answer the questions​
Dominik [7]

9514 1404 393

Explanation:

We refer to the equations as [1] and [2]. We refer to the items as (1) – (4).

__

1. The terms to be eliminated have matching coefficients in (1) and (2). They can be eliminated by subtracting one equation from the other.

In (3) and (4), putting the equations in standard form* results in terms with opposite coefficients. Those terms can be eliminated by adding the equations.

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2. Terms to be eliminated will have matching or opposite coefficients.

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3. In (1) and (2), the variable x can be eliminated by subtracting one equation from the other. In the attachment, we have indicated the subtraction that will result in the remaining variable having a positive coefficient.

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4. In (3) and (4), the coefficients of the variables are not equal or opposite in the two equations, so no variable can be eliminated directly.

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5. As suggested by the answer to Q4, an equivalent equation must be found that has an equal or opposite variable coefficient with respect to the other equation. The new equations are ...

  (3) [2] ⇒ x -y = 2

  (4) [1] ⇒ 2x +2y = 3

_____

Here are the solutions:

(1) [1] -[2]  ⇒  (x +y) -(x -y) = (-1) -(3)

  2y = -4  ⇒  y = -2

  x = y +3 = 1 . . . . from [2]

  (x, y) = (1, -2)

__

(2) [2] -[1]  ⇒  (x +2y) -(x +y) = (8) -(5)

  y = 3

  x = 5 -y = 2 . . . . from [1]

  (x, y) = (2, 3)

__

(3) [1] +[2]/2  ⇒  (x +y) +(x -y) = (1) +(2)

  2x = 3  ⇒  x = 3/2

  y = 1 -x = -1/2 . . . . from [1]

  (x, y) = (3/2, -1/2)

__

(4) [2] +[1]/2  ⇒  (5x -2y) +(2x +2y) = (4) +(3)

  7x = 7  ⇒  x = 1

  y = (3 -2x)/2 = 1/2

  (x, y) = (1, 1/2)

_____

* Equations in standard form have mutually prime coefficients. In (3) a factor of 2 can be removed from equation [2]. In (4), a factor of 2 can be removed from equation [1].

7 0
3 years ago
In a right triangle, if tan x = 1/2 then what is cos x
NARA [144]

Answer:

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cos x = -------------

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Step-by-step explanation:

If tan x = 1/2 then what is cos x?  

Recall that tan x is defined as the quotient sin x / cos x, so that in this case sin x / cos x = 1 / 2 = opp side / adjacent side.  Also, recall that cos x = adj side / hypotenuse.

To determine cos x, we need to find the length of the hypotenuse.  That, in turn, through use of the Pythagorean Theorem, is √(1^2+2^2), or √5.

Then cos x = adj side / hyp = 2/√5.  Rationalizing the denominator, we get

               2√5

cos x = -------------

                   5

5 0
3 years ago
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