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FinnZ [79.3K]
3 years ago
6

Check all the statements that are true: A. If a relation is symmetric, it cannot be anti-symmetric. B. The equality relation on

the real numbers is an equivalence relation. C. If RR is a reflexive relation on a set S, then any two RR- related elements of S must also be R2R2 related. D. There are n2n2 relations from a set with n elements to itself. E. If a relation is anti-symmetric, it cannot be symmetric. F. The less than or equal relation on the real numbers fails to be an equivalence relation because it is reflexive and transitive but not symmetric. G. A relation from a set with n elements to itself can have up to n2n2 elements. H. If RR is an equivalence relation, then R2
Mathematics
1 answer:
kogti [31]3 years ago
4 0

Answer:

See explaination

Step-by-step explanation:

B. The equality relation on the real numbers is an equivalence relation.

This statement is true

C. If RR is a reflexive relation on a set S, then any two RR- related elements of S must also be R2R2 related.

This statement is true

F. The less than or equal relation on the real numbers fails to be an equivalence relation because it is reflexive and transitive but not symmetric

This statement is true

H. If RR is an equivalence relation, then R2

This statement is true

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There is a bag filled with 3 blue and 4 red marbles.
tresset_1 [31]

Using the hypergeometric distribution, it is found that there is a 0.4286 = 42.86% probability of getting 2 of the same colour.

The marbles are chosen without replacement, hence the <em>hypergeometric </em>distribution is used to solve this question.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • N is the size of the population.
  • n is the size of the sample.
  • k is the total number of desired outcomes.

In this problem:

  • There is a total of 3 + 4 = 7 marbles, hence N = 7.
  • Of those, 3 are blue, hence k = 3.
  • 2 marbles will be taken, hence n = 2.

The probability of getting 2 of the same colour is the sum of P(X = 0), which is both red, with P(X = 2), which is both blue, then:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,7,2,3) = \frac{C_{3,0}C_{4,2}}{C_{7,2}} = 0.2857

P(X = 2) = h(2,7,2,3) = \frac{C_{3,2}C_{4,0}}{C_{7,2}} = 0.1429

Hence:

p = P(X = 0) + P(X = 2) = 0.2857 + 0.1429 = 0.4286

0.4286 = 42.86% probability of getting 2 of the same colour.

You can learn more about the hypergeometric distribution at brainly.com/question/4818951

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Answer:

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