Answer:
(a). 72.9%.
(b). 13.6 hr.
Step-by-step explanation:
So, we are given the following data or parameters or information which is going to assist us in solving this question/problem;
=> "A welder produces 7 welded assemblies during the first day on a new job, and the seventh assembly takes 45 minutes (unit time). "
=> The worker produces 10 welded assemblies on the second day, and the 10th assembly on the second day takes 30 minutes"
So, we will be making use of the Crawford learning curve model.
T(7) + 10 = T (17) = 30 min.
T(7) = T1(7)^b = 45.
T(17 ) = T1(17)^b = 30.
(T1) = 45/7^b = 30/17^b.
45/30 = 7^b/17^b = (7/17)^b.
1.5 = (0.41177)^b.
ln 1.5 = b ln 0.41177.
0.40547 = -0.8873 b.
b = - 0.45696.
=> 2^ -0.45696 = 0.7285.
= 72.9%.
(b). T1= 45/7^ - 045696 = 109.5 hr.
V(TT)(17) = 109.5 {(17.51^ - 0.45696 – 0.51^ - 0.45696) / (1 - 0.45696)} .
V(TT) (17) = 109.5 {(4.7317 - 0.6863) / 0.54304} .
= 815.7 min .
= 13.595 hr.
Answer: $4,365.10
Step-by-step explanation:
Ok, we know that:
The account starts with $2350
There is a simple interest of 3.75% (or 0.035).
Then after one year, the amount in the account will increase by 3.75%, this means that the amount will be:
$2350 + 0.035*$2350 = (1.035)*$2350.
After another year, we have the same increase (but applied to the new amount in the account):
(1.035)*$2350 + 0.035*(1.035)*$2350. = (1.035)^2*$2350
And so on.
You already can see the pattern here, the amount of money in the saving account after N years will be:
M(N) = $2350*(1.035)^N.
Now we can answer:
what is the balance of the account if it earns a simple interest of 3.75% for 18 years?
Just replace N by 18 in that equation:
M(18) = $2350*(1.035)^18 = $4,365.10
Answer:
2X
Step-by-step explanation:
bill has X and Ben has twice X so Ben has 2X
..........................0........ lol
Answer:
hdmi po ung sagot
Step-by-step explanation:
<h2>
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