Over the course of a multi-stage 4510-km bicycle race, the front wheel of an athlete's bicycle makes 1.70x106 revolutions. How m
1 answer:
Answer:
The wheel have made revolutions.
Step-by-step explanation:
The total distance traveled during the race is
D = 4510km [(1000m)/(1km)] =
The radius (r1) of the smaller bicycle wheel is
r1 =
Than the larger wheel has a radius
r2 = 0.329 m + 0.012 m = 0.341 m
Over the same distance this wheel would make N2 revolutions
N2 =
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Answer:
Step-by-step explanation:
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3x * x = 3x^2
3x * 2x = 6x^3
So 3x is a factor of 3x^2 - 6x^3.
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Answer:
√2:1
Step-by-step explanation:
First we need to know that the length of the side of the square is equal to the diameter of the inscribed circle i.e
L = di
Given the area of the square to be 9in², we can get the length of the square.
Area of a square = L²
L is the length of the square.
9 = L²
L = √9
L = 3in
Hence the length of one side of the square is 3in
This means that the diameter of the inscribed circle di is also 3in.
Circumference of a circle = π×diameter of the circle(di)
Circumference of inscribed circle = π×3
= 3π in
For the circumscribed circumscribed circle, diameter of the outer circle will be equivalent to the diagonal of the square.
To get the diagonal d0, we will apply the Pythagoras theorem.
d0² = L²+L²
d0² = 3²+3²
d0² = 9+9
d0² = 18
d0 = √18
d0 = √9×√2
d0 = 3√2 in
Hence the diameter of the circumscribed circle (d0) is 3√2 in
Circumference of the circumscribed circle = πd0
= π(3√2)
= 3√2 π in
Hence, ratio of the circumference of the circumscribed circle to the one of the inscribed will be 3√2 π/3π = √2:1
