Question

Over the course of a multi-stage 4510-km bicycle race, the front wheel of an athlete's bicycle makes 1.70x106 revolutions. How many revolutions would the wheel have made during the race if its radius had been 1.3 cm larger

Answer 1

Answer:

The wheel have made $2.10 * 10^{6} m$ revolutions.

Step-by-step explanation:

The total distance traveled during the race is

D = 4510km [(1000m)/(1km)] = $4510 * 10^{3} m$

The radius (r1) of the smaller bicycle wheel is

r1 = $\frac{D}{2*pi*N1} = \frac{4510 * 10^{3} m }{2*pi*(2.18*10^{6}) } =0.329 m$

Than the larger wheel has a radius

r2 = 0.329 m + 0.012 m = 0.341 m

Over the same distance this wheel would make N2 revolutions

N2 = $\frac{D}{2*pi*r2} = \frac{4510 * 10^{3} m }{2*pi*(0.341) } = 2.10 * 10^{6} m$