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Gre4nikov [31]
3 years ago
5

Madeline's credit card had an APR of 18.96% all of last year, and interest was compounded periodically throughout the year. Whic

h of these statements accurately describes the effective interest rate of Madeline's credit card last year?
A. It was less than 18.96% whether interest was compounded daily or monthly.

B. It was greater than 18.96% whether interest was compounded daily or monthly.

C. It was greater than 18.96% if interest was compounded daily but not if interest was compounded monthly.

D. It was less than 18.96% if interest was compounded daily but not if interest was compounded monthly.
Mathematics
2 answers:
Sauron [17]3 years ago
6 0

Answer:

It was greater than 18.96 whether interest was compounded daily or monthly

Step-by-step explanation:

Charra [1.4K]3 years ago
6 0

Answer:

Option B is correct, that is It was greater than 18.96% whether interest was compounded daily or monthly.

Step-by-step explanation:

Given: APR of Madeline's Credit Card = 18.96 %

We need to find effective Interest rate of Madeline's credit card when compounded daily or compounded monthly.

Formula for Effective Interest is,

Effective\:Rate=(1+\frac{r}{n})^n-1

where, r is normal rate and n is number of periods.

When rate is compounded daily,

we have, r = 18.96% and n = 365

Effective\:Rate=(1+\frac{\frac{18.96}{100}}{365})^{365}-1=20.87\,%.

When rate is compounded monthly,

we have, r = 18.96% and n = 12

Effective\:Rate=(1+\frac{\frac{18.96}{100}}{12})^{12}-1=20.7\,%.

Therefore, Option B is correct, that is It was greater than 18.96% whether interest was compounded daily or monthly.

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Una torre de 28.2 m de altura esta situada a la orilla de un rio, desde lo alto del edificio el ángulo de depresión a la orilla
Svet_ta [14]

Answer:

El ancho del río es 59.9 metros.

Step-by-step explanation:

El ancho del río lo podemos calcular con la siguiente relación trigonométrica asumiendo que la torre forma un triángulo rectángulo con el río:

tan(\theta) = \frac{CO}{CA}

En donde:

CA: es el cateto adyacente = Altura de la torre = 28.2 m

CO: es el cateto opuesto = ancho del río =?

θ: es el ángulo adyacente a CA

Dado que el ángulo de depresión (25.2°) está ubicado fuera de la parte superior de la hipotenusa del triángulo que forma la torre con la orilla opuesta del río, debemos calcular el ángulo interno (θ) como sigue:

\theta = (90 - 25.2)^{\circ} = 64.8 ^{\circ}

Ahora, el ancho del río es:

CO = tan(\alpha)*CA = tan(64.8)*28.2 = 59.9 m

Por lo tanto, el ancho del río es 59.9 metros.

Espero que te sea de utilidad!                  

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Dafna11 [192]
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Each figure shows a triangle with one of its angle bisectors.<br> 12) 22 - 38°. Find mZTRS.
jarptica [38.1K]

Answer:

76 degrees

Step-by-step explanation:

this special line is an angle bisected.

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