You'd multiply 8 by 4 to get 32, and then add 2 to get 34, which is the mans age. I hope this helps!
KE=1/2mv^2
50000=(0.5)(1000)v^2
v^2=50000/500
v^2=100
v=10 ms^-1
Answer:
Hi how are you doing today Jasmine
Answer:
Two possible lengths for the legs A and B are:
B = 1cm
A = 14.97cm
Or:
B = 9cm
A = 12cm
Step-by-step explanation:
For a triangle rectangle, Pythagorean's theorem says that the sum of the squares of the cathetus is equal to the hypotenuse squared.
Then if the two legs of the triangle are A and B, and the hypotenuse is H, we have:
A^2 + B^2 = H^2
If we know that H = 15cm, then:
A^2 + B^2 = (15cm)^2
Now, let's isolate one of the legs:
A = √( (15cm)^2 - B^2)
Now we can just input different values of B there, and then solve the value for the other leg.
Then if we have:
B = 1cm
A = √( (15cm)^2 - (1cm)^2) = 14.97
Then we could have:
B = 1cm
A = 14.97cm
Now let's try with another value of B:
if B = 9cm, then:
A = √( (15cm)^2 - (9cm)^2) = 12 cm
Then we could have:
B = 9cm
A = 12cm
So we just found two possible lengths for the two legs of the triangle.
It's C because for the perpendicular line, you need to construct cross points to draw it through.
- you start by drawing a random circle with F as the center, just as long as it intersects line DE
- Then you use the intersections of that circle to draw new circles starting at F.
- These new circles intersect at F and another point below DE.
- You draw the perpendicular line through F and the other point.
