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3 years ago

Any 5 algebraic formulas

Mathematics

2 answers:

Ostrovityanka [42]3 years ago

6 0

Answer:

a2 – b2 = (a – b)(a + b)

(a + b)2 = a2 + 2ab + b2

a2 + b2 = (a + b)2 – 2ab

(a – b)2 = a2 – 2ab + b2

(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca

(a – b – c)2 = a2 + b2 + c2 – 2ab + 2bc – 2ca

(a + b)3 = a3 + 3a2b + 3ab2 + b3 ; (a + b)3 = a3 + b3 + 3ab(a + b)

(a – b)3 = a3 – 3a2b + 3ab2 – b3 = a3 – b3 – 3ab(a – b)

a3 – b3 = (a – b)(a2 + ab + b2)

a3 + b3 = (a + b)(a2 – ab + b2)

(a + b)4 = a4 + 4a3b + 6a2b2 + 4ab3 + b4

(a – b)4 = a4 – 4a3b + 6a2b2 – 4ab3 + b4

a4 – b4 = (a – b)(a + b)(a2 + b2)

a5 – b5 = (a – b)(a4 + a3b + a2b2 + ab3 + b4

lara [203]3 years ago

5 0

Answer:

a2 – b2 = (a – b)(a + b)

(a + b)2 = a2 + 2ab + b2

a2 + b2 = (a + b)2 – 2ab

(a – b)2 = a2 – 2ab + b2

(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca

(a – b – c)2 = a2 + b2 + c2 – 2ab + 2bc – 2ca

(a + b)3 = a3 + 3a2b + 3ab2 + b3 ; (a + b)3 = a3 + b3 + 3ab(a + b)

(a – b)3 = a3 – 3a2b + 3ab2 – b3 = a3 – b3 – 3ab(a – b)

a3 – b3 = (a – b)(a2 + ab + b2)

a3 + b3 = (a + b)(a2 – ab + b2)

(a + b)4 = a4 + 4a3b + 6a2b2 + 4ab3 + b4

(a – b)4 = a4 – 4a3b + 6a2b2 – 4ab3 + b4

a4 – b4 = (a – b)(a + b)(a2 + b2)

a5 – b5 = (a – b)(a4 + a3b + a2b2 + ab3 + b4)

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FinnZ [79.3K]

Answer:

wait you want me to answer this

5 0

3 years ago

Which is not a correct way to rewrite this expression using the distributive

Effectus [21]

Given:

The expression is

$(2x^2+4x-7)(x-2)$

To find:

The expression which is not a correct way to rewrite the given expression.

Solution:

We have,

$(2x^2+4x-7)(x-2)$

Using distributive property, we get

$=(2x^2)(x-2)+(4x)(x-2)+(-7)(x-2)$

$=(2x^2)(x)+(2x^2)(-2)+(4x)(x)+(4x)(-2)+(-7)(x)+(-7)(-2)$

Using distributive property the given expression can rewritten as:

$=(2x^2+4x-7)(x)+(2x^2+4x-7)(-2)$

Only the expression in option A is not a correct way to rewrite the given expression because $(2x^2+4x-7)$ is not distributed to $(x-2)$ properly.

Therefore, the correct option is A.

3 0

3 years ago

Which are solutions of the equation x2 - 16 = 0? Check all that apply.

Setler [38]

Answer:

x=-4

x=4

Step-by-step explanation:

We can factor x^2 -16 = 0 by recognizing that it is a difference of squares. That means we can factor the equation to (x-4)(x+4) = 0. By using the Zero Product Property we know that either (x-4) or (x+4) is equal to 0. That means that x either equals -4 or 4.

8 0

3 years ago

Read 2 more answers

Which of the following statements are true of the graph of the function f(x)= (x+5)(x-3).

alexandr1967 [171]

Answer:

4 is the correct answer

Step-by-step explanation:

y=(x+5)(x-3)

so x intercept means the value of x when y is zero

0=(x+5)(x-3)

x+5=0 so x=-5