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4 years ago

Find the length of line segment AB where A is (-6,-2) and B is (7,-8)

Mathematics

1 answer:

Feliz [49]4 years ago

6 0

Answer:

The length is √205 or 14.3178 units in decimal form.

can you please mark brainliest again because my answer got DELETED because sometimes brainly doesn't know what it's doing and the mods delete correct answers for no reason. DANG IT WEGNER

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I need to know what is 5*4^5

Ksivusya [100]

5120 is the answer!:)

3 0

3 years ago

Will someone please help me? I will give brainliest

zavuch27 [327]

Answer:

A, E

Step-by-step explanation:

We can use rules of fractions and negatives to determine that B, C, and D are incorrect and A and E are correct.

4 0

3 years ago

NEED HELP!! Trigonometry questions

anzhelika [568]

Answer:

Step-by-step explanation:

Question 1: Assumption: This is a 30-60-90 triangle.

Remember that the sides of a 30-60-90 triangle are in the ratio 1:√3:2

The side opposite the 90° angle is 16, so the side opposite the 30° angle is 16/2 = 8

x = 8 units.

:::::

Question 2: Assumption: This is an isosceles triangle.

Draw the altitude to the vertex angle and you get a 30-60-90 triangle.

The side opposite the 90° angle has length 22, so the side opposite the 30° angle has length 11.

x/2 = 11

x = 22 units

:::::

Question 3: Assumption: This is a 45-45-90 triangle.

The sides of a 45-45-90 triangle are in the ratio 1:1:√2

The sides opposite the 45° angles are 19 and x.

x = 19

:::::

Question 4: Assumption: This is an isosceles triangle.

x = 13 units

:::::

Question 5: Assumption: This is a right triangle.

sin(54°) = x/45

x = 45sin(54°) ≅ 36.4 units

:::::

Question 6: Assumption: This is a right triangle.

sin(35°) = z/23

z = 23sin(35°) ≅ 13.2 units

4 0

3 years ago

Packaging By cutting away identical squares from each corner of a rectangular piece of cardboard and folding up the resulting fl

Kobotan [32]

Answer:

The dimension of the box is 18.66 in by 2.66 in by 1.17 in.

Step-by-step explanation:

Given that, The cardboard is 21 in. long and 5 in. wide.

Assume,x be the length of the each sides of the square .

Then the length of the box is = (21-2x) in.

The breadth of the box is =(5-2x) in.

The height of the box is = length of side of the square

= x in.

The volume of the box = length × wide × height

=(21-2x)(5-2x)x

=(105-52x+4x²)x

=( $105 x-52x^2+4x^3$ )

Let

V= $105 x-52x^2+4x^3$

Differentiating with respect to x

$V'=105-104x+12x^2$

Again differentiating with respect to x

$V''=-104+24x$

To find the dimension of the box, we set V'=0

$105-104x+12x^2=0$

Applying the quadratic formula $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ , here a=12, b= -104 and c =105

$\Rightarrow x=\frac{-(-104)\pm\sqrt{(-104)^2-4.12.105}}{2.12}$

$=\frac{104\pm 76}{24}$

=7.5, 1.17

For x= 7.5 , the wide of the box will be negative.

∴x=1.17 in.

$V''_{x=1.17}=-104+(24\times 1.17)$

Since at x= 1.17, V''<0 , therefore at x=1.17 in. the volume of the given box will be maximum.

The length of the box is = [21-(1.17×2)]=18.66 in.

The wide of the box is = [5-(1.17×2)]=2.66 in.

The height of the box is = 1.17 in.

The dimension of the box is 18.66 in by 2.66 in by 1.17 in.

5 0

4 years ago

I will get my points but answer it correctly and no LINKS!!! (factotise by using a suitable identity X5-X)

9966 [12]

x(x-1)(x+1)(x²+1)=0

Hope it helps you

6 0

3 years ago