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Rufina [12.5K]
3 years ago
8

Solve 6t raise to power2 equal 25t plus 9 using standard form in quadratic equation​

Mathematics
2 answers:
marissa [1.9K]3 years ago
6 0

See attachment for your problem set up.

kotykmax [81]3 years ago
6 0

Answer:

t6^2=25t+9 this in stander form. Find the Quadratic Equation Given the Roots of t6^2=25t+9 .answer is (1,3) (6,4)(1,5)

Step-by-step explanation:

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ikadub [295]

Answer:

Step-by-step explanation:

1)    a = x - 5

a)   z = y + 5

b)  z = y - 3

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5 0
2 years ago
how do I find the area of an equilateral triangle given the perimeter of 60 and the height of 17.3 cm?
guajiro [1.7K]
If perimeter is 60 so the side is 60 ÷ 3 = 20

Now we can apply the area formula for triangles;

A=\frac{1}{2}.b.h\\
\\
A=\frac{1}{2}.20.17.3=10.17.3=173 \ cm^2
3 0
3 years ago
Find the surface of the figure.<br><br><br> A) 348 m2<br> B) 347 m2<br> C) 174 m2<br> D) 360 m2
Verizon [17]
Answer :c
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6 0
1 year ago
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Anastasy [175]
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3 0
3 years ago
If the angles are represented in degrees,find both angles: csc(2x+9) =sec(3x+26) Please respond quick
Olenka [21]

Answer:

Before solving the given trigonometric relation change everything to sines and cosines

Step-by-step explanation:

consider the given equation;

1/sin(2x+9)=1/cos(3x+26)

Multiplying the above equation on both sides by cos(3x+26)sin(2x+9) then we get,

cos(3x+26)=sin(2x+9)

By using identity,cos a=sin(90-a) expand above equation we will get,

sin(90-(3x+26))=sin(2x+9)

Then,

90-3x+26=2x+9

x=11

So the required value of the angle is 11 degree.

3 0
2 years ago
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