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Rufina [12.5K]
3 years ago
8

Solve 6t raise to power2 equal 25t plus 9 using standard form in quadratic equation​

Mathematics
2 answers:
marissa [1.9K]3 years ago
6 0

See attachment for your problem set up.

kotykmax [81]3 years ago
6 0

Answer:

t6^2=25t+9 this in stander form. Find the Quadratic Equation Given the Roots of t6^2=25t+9 .answer is (1,3) (6,4)(1,5)

Step-by-step explanation:

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Find the slope of the line that passes through these two points: (- 1, 0) and (4, - 2) .
I am Lyosha [343]
Slope is vertical change over horizontal change. Since coordinates conveniently give both the horizontal and vertical coordinates of a points, we can use the coordinates of both points to differentiate, or find the change horizontally and the change vertically between the two points.
8 0
3 years ago
Please help. Find the value of x. Round to
Law Incorporation [45]

Answer:

x =13.7

Step-by-step explanation:

Given

See attachment

Required

Find x

The relationship between x, 47 and 17^{\circ} is:

sin(17^{\circ}) = \frac{x}{47}

i.e.

sin(\theta) = \frac{Opposite}{Hypotenuse}

Solving further:

sin(17^{\circ}) = \frac{x}{47}

Make x the subject

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x = 47 * 0.2924

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<em></em>x =13.7<em> --- approximated</em>

3 0
3 years ago
¼ log b x – 2 log b 5 – 10log b y
melamori03 [73]

I will leave out the base, b since it's the same for all these logarithms.

\frac{1}{4} Log(x)-2Log(5)-10Log(y)  \\  \\ Power-Rule \\  \\ Log( x^{ \frac{1}{4} } )-Log( 5^{2} )-Log( y^{10} ) \\  \\ Quotient-Rule \\  \\ Log( x^{ \frac{1}{4} } ) -Log( \frac{25}{ y^{10} } ) \\  \\ Quotient-Rule \\  \\ Log( \frac{ x^{ \frac{1}{4} }  y^{10} }{25} )


7 0
3 years ago
Find all points on the circle (x^2) + (y^2) = 676 where the slope is 5/12
borishaifa [10]
Implicit defferentation

remember that dy/dx y= dy/dx


so
take derivitive of both sides
2x+2y \space\ \frac{dy}{dx}=0
solve for \frac{dy}{dx}
minus 2x both sides
2y \space\ \frac{dy}{dx}=-2x
divide both sides by 2y
\frac{dy}{dx}=\frac{-2x}{2y}
\frac{dy}{dx}=\frac{-x}{y}

when is the slope equal to \frac{5}{12}
solve for \frac{dy}{dx}=\frac{5}{12}
\frac{dy}{dx}=\frac{5}{12}
\frac{5}{12}=\frac{-x}{y}
5y=-12x
y=\frac{-12}{5}x
find where the circle and this line intersects

substitute \frac{-12}{5}x for y
x^2+(\frac{-12}{5}x)^2=676
x^2+\frac{144}{25}x^2=676
\frac{25}{25}x^2+\frac{144}{25}x^2=676
\frac{169}{25}x^2=676
times both sides by \frac{25}{169}
x^2=100
sqrt both sides, take positive and negative roots
x=+/-10

sub back

y=\frac{-12}{5}x
y=(\frac{-12}{5})(10) \space\ or \space\ (\frac{-12}{5})(-10)
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the points are (10,-24) and (-10,24)
8 0
3 years ago
Given sec A = 5/3 and that angle A is in Quadrant I, find the exact value of csc A in simplest radical form using a rational den
serg [7]

9514 1404 393

Answer:

  5/4

Step-by-step explanation:

The relationship between the sec and csc functions is ...

  csc(A) = sec(A)/√(sec²(A) -1)

For the given value of sec(A), this is ...

  csc(A) = (5/3)/√((5/3)² -1) = (5/3)/√(16/9) = (5/3)/(4/3)

  csc(A) = 5/4

__

Some calculators can tell you the answer directly.

5 0
3 years ago
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