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2 years ago

I need help on this question

Mathematics

1 answer:

Morgarella [4.7K]2 years ago

6 0

Answers : A and D

Step - by - step explanation :

tip : when finding constant of proportionality it's always Y divided by X

A = what is 22.5 divided by 3 ? 7.5 ( now multiply 7.5 by the next X [ 4 ] )

what is 7.5 x 4 ? 30 ( and since on the graph it also says 30 then you can assume this one has a proportional relationship )

B = what is 12 divided by 3 ? 4 ( now multiply 4 by the next X [ 5 ] )

what is 4 x 5 ? 20 ( and because the graph says 25 then you know it's NOT a proportional relationship )

C = what is 8.5 divided by 2 ? 4.25 ( now multiply 4.25 by the next X [ 5 ] )

what is 4.25 x 5 ? 21.25 ( and because the graph says 22.5 then you know it's NOT a proportional relationship )

D = what is 10 divided by 2 ? 5 ( now multiply 5 by the next X [ 3 ] )

what is 5 x 3 ? 15 ( and since on the graph it also says 15 then you can assume this one has a proportional relationship )

( sorry it took me so long to write this )

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Here are the monthly charges for Jo's mobile phone

yaroslaw [1]

Answer:

The correct answer is - 625.36.

Step-by-step explanation:

Given:

Fixed mothly plan - 616

free minutes - 150

Used minutes - 170

Free text - 150

Used text - 182

Charging amount over free limit - 18p

Solution:

Number of minutes over the limit - 170 - 150 = 20

Number of text over the limit - 182 - 150 = 32

So the extra amount that will be add to the monthly charge would be -

(20*0.18) +(32*0.18)

and the total charge of the month would be -

= 616+(20*0.18) +(32*0.18)

= 616+3.60+5.76

= 625.36

Thus, the correct answer would be - 625.36

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3 years ago

subtracting 1 to the product of 5 and x gives the same value as adding 10 to the product of 3 and x. what value of x makes the s

STatiana [176]

Answer:

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3 years ago

Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

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2 years ago

42. The diagram represents a ramp in the shape of a right triangle and the lengths

oee [108]

The length of the ramp is 61 feet.

<h3>What is the length of the ramp?</h3>

In order to determine the length of the ramp, Pythagoras theorem would be used.

The Pythagoras theorem: a² + b² = c²

where a = length

b = base

c = hypotenuse

√11² + 60²

√121 + 3600

√3721

= 61 feet

Please find attached the image of the ramp. To learn more about Pythagoras theorem, please check: brainly.com/question/14580675

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2 years ago

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Answer:

Step-by-step explanation:

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Denoting all the 9 savory dishes by $p_1, p_2,...,p_9$ , and all the sweet dishes by $q_1,q_2,...,q_5$ .

The possible different mix-and-match plates consisting of two savory dishes are as follows:

There are 9 plates with $q_1$ from sweet plates which are $(q_1, p_1), (q_1, p_2), ..., (q_1,p_9).$

There are 9 plates with $q_2$ from sweet plates which are $(q_2, p_1), (q_2, p_2), ..., (q_2,p_9).$

Similarly, there are 9 plated for each $q_3, q_4$ and $q_5.$

Hence, the total number of the different mix-and-match plates consisting of two savory dishes

$= 9+9+9+9+9= 9\times5=45$

7 0

3 years ago