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4 years ago

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at 3:00a.m,the temperature is -5°F. Between 3:00a.m. and 6:00 a.m.,the temperature drops by 12°F. Between 6:00a.m. and 9:00a.m.,

the temperature rises by 4°F. What is the temperature at 9:00a.m.?

1 answer:

barxatty [35]4 years ago

4 0

-13<span>°F is the correct answer.</span>

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Svetach [21]

Answer:

no

Step-by-step explanation:

8 0

4 years ago

Read 2 more answers

Suppose the probability of a false positive result on a mammogram is 4%. Suppose that the probability of a false negative result

Mariulka [41]

Answer:

0.0049 = 0.49% probability that she actually has breast cancer

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Positive test result

Event B: Breast cancer

Probability of a positive test result:

4% of (1 - 0.0002)

98% of 0.0002

So

$P(A) = 0.04*(1 - 0.0002) + 0.98*0.0002 = 0.040188$

Having breast cancer and testing positive.

98% of 0.0002

So

$P(A \cap B) = 0.98*0.0002 = 0.000196$

What is the probability that she actually has breast cancer?

$P(B|A) = \frac{0.000196}{0.040188} = 0.0049$

0.0049 = 0.49% probability that she actually has breast cancer

8 0

3 years ago

givi [52]

Answer: The right option that represents possible inputs and outputs of the function is the ordered pair

{(-2, -18), (2, 14), (0, -2)}

Step-by-step explanation:

By crosschecking;

Y=8x-2

When x=-2 , y= 8(-2) -2 , y= -16-2, y=-18 . (-2,-18)

When x=2 , y= 8(2) -2 , y= 16-2, y= 14

(2,14)

When x=0 , y= 8(0) -2 ,y= 0-2, y= -2

(0,-2)

3 0

4 years ago

Select the correct answer from each drop-down menu. The equation (y-2)^2/3^2 - (x-2)^2/4^2=1 represents a hyperbola whose foci a

aev [14]

Answer:

The foci are (2 , 7) and (2 , -3)

Step-by-step explanation:

* lets revise the equation of the hyperbola

- The standard form of the equation of a hyperbola with

center (h , k) and transverse axis parallel to the y-axis is

(y - k)²/a² - (x - h)²/b² = 1

- The coordinates of the vertices are ( h ± a , k )

- The coordinates of the co-vertices are ( h , k ± b )

- The coordinates of the foci are (h , k ± c), where c² = a² + b²

* Now lets solve the problem

∵ The equation of the hyperbola of vertex (h , k) is

(y - k)²/a² - (x - h)²/b² = 1

∵ The equation is (y - 2)²/3² - (x - 2)²/4² = 1

∴ k = 2 , h = 2 , a = 3 , b = 4

∵ The foci of it are (h , k + c) and (h , k - c)

- Lets find c from the equation c² = a² + b²

∵ a = 3

∴ a² = 3² = 9

∵ b = 4

∴ b² = 4² = 16

∴ c² = 9 + 16 = 25

∴ c = √25 = 5

- Lets find the foci

∵ The foci are (h , k + c) and (h , k - c)

∵ h = 2 , k = 2 , c = 5

∴ The foci are (2 , 2 + 5) and (2 , 2 - 5)

∴ The foci are (2 , 7) and (2 , -3)

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4 years ago

Select the story problem that this division problem represents

podryga [215]

C.The work space in Elishas room has a width of 1/2 meter and an are of 3/5 square meter. How long is it?

hope this helps

7 0

3 years ago