Since a stop sign is an octagon it has eight sides. So the perimeter will be:
p=8x, p=perimeter and x=side length. We are told that the perimeter is equal to:
16x^2-80x so we can say:
16x^2-80x=8x subtract 8x from both sides
16x^2-88x=0 factor out 8x
8x(2x-11), since we know x>0
x=11/2
x=5.5 units
if any doubt leave a comment
If you have a graphing calculator just put in the equation in 'y=' (not the i equation), and then go to 2nd trace and see where the y=0, those numbers under the x column are the zeros. For the first one, the zeros are: -1, .5, and 2.8. For the second question the zeros are: -3 and about 1.9. The zeros with a decimal are estimations.
f(x) = 2x^2 - x - 10
Part A:
x-intercepts: (-2,0), (5/2,0)
Part B:
The vertex is the minimum
vertex: (1/4, -81/8)
Part C:
A:
x: -2, -1, 1/4, 1, 2
y: 0, -7, -81/8, -9, -4
B:
Answer:
f(0,0)=ln19
Step-by-step explanation:
is given as continuous function, so there exist 
and it is equal to f(0,0).
Put x=rcosA annd y=rsinA
we know that 
, so we have that
So f(0,0)=ln19.
