Answer:
4.44 g Ne
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
0.220 mol Ne
<u>Step 2: Identify Conversions</u>
Molar Mass of Ne - 20.18 g/mol
<u>Step 3: Convert</u>
<u />
= 4.4396 g Ne
<u>Step 4: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules and round.</em>
4.4396 g Ne ≈ 4.44 g Ne
Answer:
Glad you know what it is now!
Explanation:
Nice!!
The required mass of argon in given number of atoms of argon is 155.61 grams.
<h3>What is Avogadro's number?</h3>
Avogadro's number is the number of atoms which are present in 1 mole of any substance and it is equal to 6.022×10²³.
Relation between the mass and moles of any substance will be represented as:
- n = W/M, where
- W = given mass
- M = molar mass
So, moles of argon will be calculated by using given number of atoms as:
Moles = 2.4×10²⁴ atoms / 6.022×10²³ atoms per mole
Moles = 3.9 moles
Now mass will be:
W = (3.9mol)(39.9g/mol) = 155.61 g
Hence required mass of argon is 155.6g.
To know more about Avogadro's number, visit the below link:
brainly.com/question/1513182
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The compound is Al2O3. The ratio of aluminum to oxygen is 2:3.
