Below are the choices:
a. −166 kJ/mol
<span>b. 166 kJ/mol </span>
<span>c. 1.64 kJ/mol </span>
<span>d. 1.66 × 10^5 kJ/mol
</span>
To calculate the activation energy of a reaction, we use the Arrhenius equation. You may want to look it up to see how and why it works. In the problem you posted, there are two temperatures and two rate constants. After some rearranging and substitution of the Arrhenius equation, we have Ea = R T1 T2/(T1-T2) ln(k1/k2) = 8.314 J/mol K (600 K)(650 K)/(600 K-650 K) ln(2.7×10^-4 M^−1sec^−1/3.5×10^−3 M−^1sec^−1) = 166145 J/mol = 166 kJ/mol => choice b
Answer:
For mole conversion always remember 1 mole of compound = molar mass of compound.
Ex. 2 moles H20 to grams
2mol H2O x 18 g / 1mol H20
For molecules use Avogadro's number like moles multiplied to 6.022x10²³ answer will be in molecules.
Explanation:
Answer:
The answer to your question is: density = 5 g/cm³
Explanation:
Data
Volume = v = 2 m³
mass = m = 1 x 10⁴ kg
Density = d = ? g/cm³
Formula
density = mass/volume
Volume
1 m³ ------------------- 1 000 000 cm³
2 m³ ------------------ x
x = (2 x 1 000 000) / 1
x = 2 000 000 cm³
Mass
1 kg ------------------ 1000 g
1 x 10⁴ kg ------------ x
x = (1 x 10⁴ x 1000) / 1
x = 10 000 000 g
density = (10 000 000) / 2 000 000
density = 5 g/cm³
