The solution to the problem is as follows:
<span>a)
C + O2 = CO2
Molar mass CO2 = 44 g/mol
3.67 g CO2 * 1 mol / 44 g =
=0.0834 mol CO2 = 0.0834 mol C
I hope my answer has come to your help. God bless and have a nice day ahead!
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Phenobarbital is derivative of
Barbituric Acid and Barbituric Acid is derivative of
Urea. (structures shown in Fig below)
Urea has H</span>₂N- group attached to Carbonyl Group (C=O), and such class of comounds conataining H₂N-C=O bond are called as Amides.
Result: So, <span>Phenobarbital belongs to
Amides.</span>
Answer:
Given that W=mg:
The weight of the box would be 50 N taking the value of 'g' as 10ms-2. Taking the value of 'g' as 9.8ms-2, the weight of the box would be 49 N.
(N = Newtons)
Answer:
Explanation:
(a) melting point of S,S-hydrobenzoin should be 140°C. Since S,S-hydrobezoin and R,R-hydrobenzoin are enantiomeric pair so that their melting point and boilong point should be same.
(b) different melting point,
Racemic mixture must have different melting point in comparison to the pure enantiomers.
considering a racemic mixture, individual enantiometer possesses a greater affinity for its kind of molecules than for those of the other enantiometer