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alexgriva [62]
2 years ago
10

A constantly changing and developing resume means that you are always _______________ as a person and potential employee. A. cha

nging and developing B. failing C. succeeding D. remaining the same
Chemistry
1 answer:
abruzzese [7]2 years ago
4 0
I believe your answer is A “changing and developing”

Good luck!
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What does ultraviolet light from the sun do with oxygen gas.
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Gases in Earth's atmosphere form a protective layer

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3 years ago
A 5% Dextrose solution is diluted with sterile water. The volume of the sterile water added is 40% of the volume of the Dextrose
baherus [9]

Answer:

4.90% is approximately the new Dextrose concentration.

Explanation:

Volume by Volume percent is given by ;

(v/v)\%=\frac{\text{Volume of solute}}{\text{Volume of solution}}\times 100

Volume percentage of dextrose solution = 5%

In 100 mL of solution 5 ml of dextrose is present.

Now, volume sterile water added was equal to the 40% of volume of dextrose volume.

So, volume of the sterile water added = \frac{40}{100}\times 5 ml = 2 mL

Total volume of the solution after addition of water = 100 mL + 1 mL = 102 mL

New concentration of dextrose will be;

(v/v)\%=\frac{\text{Volume of solute}}{\text{Volume of solution}}\times 100

\frac{5 mL}{102 mL}\times 100=4.90\%

4.90% is approximately the new Dextrose concentration.

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3 years ago
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4 years ago
liquid water at 50 degrees celsius and 1 bar is superheated to produce steam, at 350 degrees celsius and 5 bar. What is the chan
vazorg [7]

Answer:

Δ h = 2958.9 kJ/kg

Explanation:

initial state

T₁ = 50⁰C

P₁ = 1 bar

from steam table , Enthalpy at 50⁰C and 1 bar

h₁ = 208.785 kJ/kg

final state

T₂ = 350⁰C

P₂ = 5 bar

from steam table , Enthalpy at 350⁰C and 5 bar

h₂ = 3167.75 kJ/kg

change in entalpy for the process

Δ h = h₂  - h₁

      = 3167.75  - 208.785

 Δ h = 2958.965 kJ/kg

the change in enthalpy is equal to  Δ h = 2958.9 kJ/kg

5 0
3 years ago
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