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grigory [225]
3 years ago
13

Find the distance between H(13,8), X(-6, -6)

Mathematics
1 answer:
zmey [24]3 years ago
7 0
The answer is use Photomath
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If you know how to this and can help that would be so great...also please take a look at my last question Thanks
Alik [6]

Answer:

im sorry i dont know

Step-by-step explanation:

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3 years ago
Line m passes through the points (4, 1) and (7, 3) while line n passes through the points (-3, 5) and (-9, 1). Which statement a
VARVARA [1.3K]
The correct answer is <span>C. Lines m and n have the same slope so they are parallel. The slope = 2/3 </span>
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3 years ago
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A survey found that women's heights are normally distributed with mean 62.8 inches and standard deviation of 2.5 inches. This su
Jet001 [13]
<span>a) 

Z*_Upper = (76 - 62.7)/2.5 = 5.32

Z*_Lower = (57 - 62.7)/2.5 = -2.28 

The requirement is to get p(-2.28 < Z < 5.32) = p(Z<5.32) - p(Z<-2.28). 

Use normal distribution table to get the answer for p and multiply with 100 to get the percentage. 

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4 0
3 years ago
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Pls Help! John wants to prove ABC = to DEF. He Knoes AB = DE and AC = DF. With Screenshot
matrenka [14]

Answer:

\angle A \cong \angle D

Step-by-step explanation:

The Side-Angle-Side method cana only be used when information given shows that an included angle which is between two sides of a ∆, as well as the two sides of the ∆ are congruent to the included side and two sides of the other ∆.

Thus, since John already knows that \overline{AB} \cong \overline{DE} and \overline{AC} \cong \overline{DF}, therefore, an additional information showing that the angle between \overline{AB} and \overline{DE} in ∆ABC is congruent to the angle between \overline{AC} and \overline{DF} in ∆DEF.

For John to prove that ∆ABC is congruent to ∆DEF using the Side-Angle-Side method, the additional information needed would be \angle A \cong \angle D.

See attachment for the diagram that has been drawn with the necessary information needed for John to prove that ∆ABC is congruent to ∆DEF.

7 0
3 years ago
The cone and the cylinder below have equal surface area. True or false.
WARRIOR [948]

Answer:

False

Step-by-step explanation:

The surface area of the cone is

V=\pi r^2 +\pi rl

SA=\pi r^2 +\pi\times r\times 2r

SA=\pi r^2 +2\pi\times r^2

SA=3\pi r^2

The surface area of the cylinder is:

SA=2\pi r^2 +2\pi rh

SA=2\pi r^2 +2\pi\times r\times r

SA=4\pi r^2

3 0
3 years ago
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