X= 4
Because I need to answer a question in order to answer other questions so your welcome.
Answer:
(x-3)^2 + (y+2)^2 = 9^2
Step-by-step explanation:
x^2 -6x+y^2+4y-68 = 0
Complete the square
x^2 -6x+y^2+4y-68+68 = 0+68
x^2 -6x+y^2+4y = 68
Find the term to add for x
-6 /2 = -3 -3^2 = 9
Find the term to add for y
4/2 =2 2^2 = 4
Add 9 and 4
x^2 -6x+9+y^2+4y+4 = 68+9+4
(x-3)^2 + (y+2)^2 = 81
(x-3)^2 + (y+2)^2 = 9^2
The standard form is
(x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center and r is the radius
9514 1404 393
Answer:
C) 4
Step-by-step explanation:
The point-slope equation of the line is ...
y -k = m(x -h) . . . . . line with slope m through point (h, k)
y +9 = 3(x -1) . . . . . line with slope 3 through point (1, -9)
For y=0 (the 0 of the function), we have ...
9 = 3(x -1)
3 = x -1
4 = x
The x-intercept is (4, 0).
