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3 years ago

A Ferris wheel can accommodate 40 people in 20 minutes. How many people

Mathematics

1 answer:

Montano1993 [528]3 years ago

6 0

Answer:

360 people in 3 hours. 120 people per hour.

Step-by-step explanation:

How many times do 20 minutes go into 3 hours?

Well, 60 min. ÷ 20 min. = 3

So, 3 x 3 = 9

So 40 people went on the ride each 20 minutes. And there are (3) 20 minutes in every hour.

So 3 hours would be 9 x 40 = 360

120 people per hour because 40 x 3 = 120

and 20 minutes (3) times equals 1 hour.

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Does anyone know what the 5√2 (simplify radicals)?

maks197457 [2]

Answer:

5√2 is as simple as it gets

5√2 ≈ 7.071068

Step-by-step explanation:

One simplifies radical expressions by removing from under the radical any squares that might be there. 2 is a prime number, so has no square factors. The simplest form of this radical expression is the one given:

5√2

Your calculator can tell you the value of this irrational number is about ...

5√2 ≈ 7.071068

8 0

4 years ago

Using the work shown on the left, What is the cubed root of 4/ the square root of 2 in simplest radical form

krek1111 [17]

Answer:

⁶√2

Step-by-step explanation:

∛4 = (2^2)^1/3 = 2^2/3

So ∛4 / √2

= 2^2/3 / 2^1/2

= 2^1/6

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5 0

3 years ago

At 8:00 am, here's what we know about two airplanes: Airplane #1 has an elevation of 80870 ft and is decreasing at the rate of 4

wel

Let's begin by listing out the information given to us:

8 am

airplane #1: x = 80870 ft, v = -450 ft/ min

airplane #2: x = 5000 ft, v = 900ft/min

We must note that the airplanes are moving at a constant speed. The equation for the airplanes is given by:

$\begin{gathered} E=x_1+vt----1 \\ E=x_2+vt----2 \\ where\colon E=elevation,ft;x=InitialElevation,ft; \\ v=velocity,ft\text{/}min;t=time,min \\ x_1=80,870ft,v=-450ft\text{/}min \\ E=80870-450t----1 \\ x_2=5,000ft,v=900ft\text{/}min \\ E=5000+900t----2 \end{gathered}$

We equate equations 1 & 2 to get the time both airlanes will be at the same elevation. We have:

$\begin{gathered} 5000+900t=80870-450t \\ \text{Add 450t to both sides, we have:} \\ 900t+450t+5000=80870-450t+450t \\ 1350t+5000=80870 \\ \text{Subtract 5000 from both sides, we have:} \\ 1350t+5000-5000=80870-5000 \\ 1350t=75870 \\ \text{Divide both sides by 1350, we have:} \\ \frac{1350t}{1350}=\frac{75870}{1350} \\ t=56.2min \\ \\ \text{After }56.2\text{ minutes, both airplanes will be at the same elevation} \end{gathered}$

The elevation at that time (when the elevations of the two airplanes are the same) is given by substituting the value of time into equations 1 & 2. We have:

$\begin{gathered} E_1=80870-450t \\ E_1=80870-450(56.2) \\ E_1=80870-25290 \\ E_1=55580ft \\ \\ E_2=5000+900t \\ E_2=5000+900(56.2) \\ E_2=5000+50580 \\ E_2=55580ft \\ \\ \therefore E_1\equiv E_2=55580ft \end{gathered}$

6 0

1 year ago

How can you write a percent as an equivalent fraction?

erik [133]

Answer:

It should be A

Step-by-step explanation:

I hope this helps

5 0

3 years ago

Help me out with this please

makvit [3.9K]

Damian : xE [-2 ; 3)

Range : yE [ 4 ; -5]

4 0

1 year ago