Can you choose a starting point so that the first 5 numbers in your sequence are all positive? Explain your reasoning.
1 answer:
Answer:
Take the starting point as the first natural number that is 1.
Step-by-step explanation:
To find: a starting point so that the first 5 numbers in the sequence are all positive
Solution:
Natural numbers are numbers that are used for counting.
Natural numbers are basically positive integers.
Take the starting point as the first natural number that is 1.
The next point as 2.
The next point as 3.
The next point as 4.
The next point as 5.
So, the sequence becomes so that the first 5 numbers in the sequence are positive.
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Answer:
Option (2)
Step-by-step explanation:
Given question is incomplete; here is the complete question.
Point A is the midpoint of side XZ and point B is the midpoint of side YZ.
Triangle XYZ is cut by line segment AB. Point A is the midpoint of side XZ and point B is the midpoint of side YZ. The length of XY is (5x - 7), the length of AB is (x + 1), and the lengths of XA and ZA are (2x - 2). The lengths of YB and BZ are congruent.
What is AX ?
2 units
4 units
6 units
8 units
From the figure attached,
XYZ is a triangle having A and B as the midpoints of the sides XZ and YZ.
By the theorem of midpoints,
AB =
Since AB = (x + 1) and XY = (5x - 7)
(x + 1) =
2x + 2 = 5x - 7
5x - 2x = 2 + 7
3x = 9
x = 3
Therefore, side AB = 3 + 1 = 4 units
Side XY = (5x - 7)
= 15 - 7
= 8 units
Side XA = 2(x - 1)
= 4 units
Therefore, Option (2) will be the answer.
