Answer: =x4+3x3+2x2−4
Step-by-step explanation:
(x2+3x+2)(x2)−4
Distribute:
=(x2)(x2)+(3x)(x2)+(2)(x2)+−4
=x4+3x3+2x2+−4
Answer:
Given that:
and 
if a , a+ commutator, it obeys 
First find:
= 
Now;
=
therefore, which implies the operators a and a+ are commutators.
Answer:
The probability that you would choose lemon-lime and then orange is 3/11 =.273.
Step-by-step explanation:
These are 'dependent events', which mean that your the event is affected by previous events. So, because you have eleven total bottles (five lemon-lime and six orange) and you do not replace the first bottle, that would only leave you with ten bottles remaining. The probability that you will pick the lemon-lime on the first choice is 5/11 because all of the bottles are there. However, your second choice will only include ten total bottles since you already took one. The probability that you would choose orange would be 6/10. When you multiply these two fractions and reduce to simplest form, you get 3/11.
Answer: <u>4 pounds</u> of brand X sugar
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Reason:
n = number of pounds of brand X sugar
5n = cost of buying those n pounds, at $5 per pound
Brand Y costs $2 per pound, and you buy 8 lbs of it, so that's another 2*8 = 16 dollars.
5n+16 = total cost of brand X and brand Y combined
n+8 = total amount of sugar bought, in pounds
3(n+8) = total cost because we buy n+8 pounds at $3 per pound
The 5n+16 and 3(n+8) represent the same total cost.
Set them equal to each other. Solve for n.
5n+16 = 3(n+8)
5n+16 = 3n+24
5n-3n = 24-16
2n = 8
n = 8/2
n = 4 pounds of brand X sugar are needed
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Check:
n = 4
5n = 5*4 = 20 dollars spent on brand X alone
16 dollars spent on brand Y mentioned earlier
20+16 = 36 dollars spent total
n+8 = 4+8 = 12 pounds of both types of sugar brands combined
3*12 = 36 dollars spent on both types of sugar brands
The answer is confirmed.
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Another way to verify:
5n+16 = 3(n+8)
5*4+16 = 3(4+8)
20+16 = 3(12)
36 = 36
