Answer:
x-intercept: (-250, 0)
y-intercept: (0, 100)
Step-by-step explanation:
Look for you the line intercepts the x-axis and y-axis. That's where the intercepts are located.
17 because 4 x 1.5 = 6, 50 / 1.5 = 33.33
Answer:
The maximum variance is 250.
Step-by-step explanation:
Consider the provided function.


Differentiate the above function as shown:

The double derivative of the provided function is:

To find maximum variance set first derivative equal to 0.


The double derivative of the function at
is less than 0.
Therefore,
is a point of maximum.
Thus the maximum variance is:


Hence, the maximum variance is 250.
Answer:
405
Step-by-step explanation:
To find sample size, use the following equation, where n = sample size, za/2 = the critical value, p = probability of success, q = probability of failure, and E = margin of error.

The values that are given are p = 0.84 and E = 0.03.
You can solve for the critical value which is equal to the z-score of (1 - confidence level)/2. Use the calculator function of invNorm to find the z-score. The value will given with a negative sign, but you can ignore that.
(1 - 0.9) = 0.1/2 = 0.05
invNorm(0.05, 0, 1) = 1.645
You can also solve for q which is 1 - p. For this problem q = 1 - 0.84 = 0.16
Plug the values into the equation and solve for n.

Round up to the next number, giving you 405.
<h3>Answer: 0.47178 Step-by-step explanation:
Find the probability for each p(X=x) up to 5 using the equation: (x-1)C(r-1)*p^r * q^x-r,
where x is number of days, p = .3 (prob of rain). q=.7 (prob of not rain), and r=2 (second day of rain). also C means choose.
So p(X=1) = 0
p(X=2) = 1C1 * .3^2 * .7^0 = .09
P(X=3) = 2C1 * .3^2 * .7^1 = .126
P(X=4) = 3C1 * .3^2 * .7^2 = .1323
P(X=5) = 4C1 * .3^2 * .7^3 = .12348
Then add all of them up
0+.09+.126+.1323+.12348 = .47178</h3>