Because of the symmetry, we can just go from x=0 to x=2 to find the area between <span>y = x^2 and y = 4 </span>
<span>that area = ∫4-x^2 dx from 0 to 2 </span> <span>= [4x - (1/3)x^3] from 0 to 2 </span> <span>= 8 - 8/3 - 0 </span> <span>= 16/3 </span>
<span>so when y = b </span> <span>x= √b </span> <span>and we have the area as </span> <span>∫(b - x^2) dx from 0 to √b </span> <span>= [b x - (1/3)x^3] from 0 to √b </span> <span>= b√b - (1/3)b√b - 0 </span>