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vladimir2022 [97]
3 years ago
14

THere are 60 dogs in the park. 20% of them are golden retrievers. How many golden retrievers are there in the park? Use a propor

tion to solve
Mathematics
1 answer:
Mrac [35]3 years ago
3 0

Answer:

There are 12 golden retrievers in the park

Step-by-step explanation:

100% is 60 dogs so if 100% is equal to 60 then 20% should be the answer.

100 ÷ 5= 20

60 ÷ 5= 12

amount of dogs in the park : golden retrievers

60 : 12

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Ok, first you have to know that 0.25 is one fourth. Finding one fourth of 60 is the first step. 1/4 of 60 is 15. Now, add 3 to 15, and you have your answer! The answer is 18 pounds.
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A rectangle has a length that is 2 greater then its width. The area is 15 square centimeters. what are the dimensions of the rec
GaryK [48]

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Answer:

  • length 5 cm
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Step-by-step explanation:

Your knowledge of multiplication facts tells you 3×5 = 15. Your knowledge of addition facts tells you 3+2 = 5. So, the dimensions 3 cm and 5 cm are the width and length of the rectangle, respectively.

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3 years ago
What is the common difference between the elements of the arithmetic sequence below?
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4 years ago
What is the answer for number 11
schepotkina [342]

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Find an identity for cos(4t) in terms of cos(t)
mestny [16]
So you can do this multiple ways, I'll do this the way that I think makes sense the l most easily.

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Cos (pi) =-1
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Now if you multiply the inside by 4, the graph oscillates more violently (goes up and down more in a shorter period).
But you can always reduce it.
Cos (0)= 1
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Cos (4pi) =Cos (2pi) =1 (Any multiple of 2pi ==1)
etc...
the pattern is that every half pi increase is now a full period as apposed to just a quarter of one. That's in theory.

Now that you know that, the identities of Cosine are another beast, but mathematically.
You have.

Cos (2×2t) = Cos^2 (2t)-Sin^2 (2t)
Sin^2 (t)=-Cos^2 (t)+1..... (all A^2+B^2=C^2)
Cos (2×2t) = Cos^2 (t)-(-Cos^2 (t)+1)
Cos (2×2t)= 2Cos^2 (2t) - 1

2Cos^2 (2t) -1= 2 (Cos^2(t)-Sin^2(t))^2 -1
(same thing as above but done twice because it's cos ^2 now)
convert sin^2
2Cos^2 (2t)-1 =2 (Cos^2 (t)+Cos^2 (t)-1)^2 -1
2 (2Cos^2(t)-1)^2 -1
2 (2Cos^2 (t)-1)(2Cos^2 (t)-1)-1
2 (4Cos^4 (t) - 2 (2Cos^2 (t))+1)-1
Distribute

8Cos^4 (t) -8Cos^2 (t) +1

Cos (4t) =8Cos^4-8Cos^2 (t)+-1






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3 years ago
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