<span>39a⁶b² and 6a²b³
</span>39a⁶b² =3*13a⁶b² = 3*13a²a⁴b² =(3a²b²)*13a⁴
6a²b³ =2*3*a²b³ =2*3*a² *b*b²=(3a²b²)*2b
so (3a²b²) is the greatest common factor
Answer:
m < b = 76
Step-by-step explanation:
Because b is directly across from the 76 degree angle, that makes them vertical angles, which means they are the same degree I believe.
Step 1) Draw a line from point F to point S. A rectangle forms (rectangle FSCW)
Step 2) Find the area of this rectangle. The area is 18 square units because it is 2 units high and 9 units across (9*2 = 18). You can count out the spaces or you can note how we go from x = -4 to x = 5 so subtracting the values gives -4-5 = -9 which has an absolute value of 9.
Step 3) Find the area of triangle FSN. The base is 9 units and the height is 6 units (count out the spaces or subtract y values). So the area is A = b*h/2 = 9*6/2 = 54/2 = 27
Step 4) Add up the area of the rectangle to the area of the triangle: 18+27 = 45
Final Answer: 45 square units
note: another way to find the answer is to find the area of rectangle WABC where point A is at (-4,4) and point B is at (5,4). Then subtract off the triangular areas of AFN and BNS
The answer is C.
SA = bh + (s1 + s2 + s3)H
SA = (6.8)(5.1) + (6.8 + 5.1 + 8.5)(2.5) = 85.68
