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Troyanec [42]
4 years ago
12

In circle C, what is the value of x?

Mathematics
1 answer:
Anna71 [15]4 years ago
5 0

Answer:x=22 degrees

Step-by-step explanation:

We are given a circle C.

Centre is at C

A line passes through the centre makes angle x and 68 on either side

A triangle is formed with angles x, 68 and another angle at the circumference.

Since the line passing through the centre is diameter of the circle, we have

the third angle of the triangle = 90 degrees ( BY semi circle angle theorem)

In the triangle sum of three angles

=90+x+68 =180

x =22 degrees

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     *<em>look at the image I attached for a better explanation</em>

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By looking at the picture, we are missing the leg's length, and by using the Pythagorean theorem, we get the equation

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You can walk 112 miles in 12 hour. <br><br> What is your average speed?
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Hi,

You can walk 9.3 miles per hour.

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4 years ago
Read 2 more answers
A class of sixty voted for class president. 30% voted for brad and 70% voted for Jane. How may votes did the winner get?
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4 years ago
Interest on $5,255 at 12 percent for 30 days (use 360 days) is:​
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Verify the identity tan(???? − ????) = tan(????)−tan(????) / 1+tan (????) tan(????) for all (???? − ????) ≠ ???? / 2 + ????n.
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Answer:

See the proof below.

Step-by-step explanation:

For this case we need to proof the following identity:

tan(x-y) = \frac{tan x - tan y}{1 + tan x tan y}

So we need to begin with the definition of tan, we know that tan x = \frac{sin x}{cos x} and we have this:

tan (x-y) = \frac{sin(x-y)}{cos(x-y)}   (1)

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sin (a-b) = sin a cos b - sin b cos a

cos(a-b) = sin a sin b + cos a cos b

And if we apply those identities into equation (1) we got:

tan(x-y) = \frac{sin x cos y - sin y cos x}{sin x sin y + cos x cos y}   (2)

We can divide numerator and denominator from expression (2) by \frac{1}{cos x cos y} like this:

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And if we simplity we got:

tan(x-y) = \frac{tan x - tan y}{tan x tan y +1 }

And with that we complete the proof. And that appies for all (x-y) \neq \frac{\pi}{2} +n\pi

6 0
4 years ago
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