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4 years ago

Solve for b: -11(2-b)<4(2b+2)

Mathematics

2 answers:

Brums [2.3K]4 years ago

4 0

b<10

-22 + 11b < 8b + 8

+22 +22

11b <8b + 30

-8b -8b

3b < 30

/3 /3

b < 10

dezoksy [38]4 years ago

3 0

First, distribute -11 to all terms in (2 - b), and 4 to all terms in (2b + 2)

-11(2 - b) = -22 + 11b

4(2b + 2) = 8b + 8

-22 + 11b = 8b + 8

Isolate the b. Add 22 to both sides, and subtract 8b from both sides.

-22 (+22) + 11b (-8b) < 8b (-8b) + 8 (+22)

11b - 8b < 8 + 22

Simplify. Combine like terms

11b - 8b < 8 + 22

3b < 30

Isolate the b. Divide 3 from both sides

(3b)/3 < (30)/3

b < 30/3

b < 10

b < 10 is your answer

hope this helps

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