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marusya05 [52]
3 years ago
11

Steve is cutting out decoration stars for his neighbors Labor day celebration. Steve has to cut out 9 stars in the last 10 minut

es. How many stars should Steve expect to cut in one hour?​
Mathematics
2 answers:
nirvana33 [79]3 years ago
4 0

Answer:

54 Stars

Step-by-step explanation:

Step 1:

60 mins = 1 Hour

Step 1:

10 × 6 = 60

Step 2:

9 × 6 = 54

Answer:

54 Stars

Hope This Helps :)

Lostsunrise [7]3 years ago
3 0

Answer:

54

In 1min star cutted= 9÷10

So in 1 hr or in60 min star cutted =60×9÷10

=54

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A scientist invents a car that can travel for many hours without stopping for fuel. The car travels around a track at 54 miles a
Alla [95]

Answer: 1,296 m iles

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:  

Distance = Speed rate x time

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Replacing with the values given and solving for D (distance)

D = 54 mph x 24 h = 1,296 m

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Feel free to ask for more if needed or if you did not understand something.

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can anyone help me its urgent. i have to get it done with the right answer by 3:25. can anybody help me and dont post saying dum
solmaris [256]

Answer:

A

Step-by-step explanation:

All pieces of data for seventh grade classes are larger than that of any kindergarten class on the table. This also proves with the mean provided.

The MAD, mean absolute deviation, helps you to identify the variation. The MAD for seventh grade was significantly larger than that of the kinder classes. The range for both sets of data is two times one another, further proving that 7th grade classes varies more.

C and D are irrelevant, and B says "varies less" which is the opposite of what's going on.

Hope that helps!

5 0
3 years ago
Read 2 more answers
The roots of the quadratic equation $z^2 + bz + c = 0$ are $-7 + 2i$ and $-7 - 2i$. What is $b+c$?
Alexxx [7]

Answer:

67

Step-by-step explanation: Given the quadratic equation $z^2 + bz + c = 0$, Vieta's formulas tell us the sum of the roots is $-b$, and the product of the roots is $c$. Thus,

\[-b = (-7 + 2i) + (-7 - 2i) = -14,\]so $b = 14.$

Also,

\[c = (-7 + 2i)(-7 - 2i) = (-7)^2 - (2i)^2 = 49 + 4 = 53.\]Therefore, we have $b+c = \boxed{67}$.

There are many other solutions to this problem. You might have started with the factored form $(z - (-7 + 2i))(z - (-7 - 2i)),$ or even thought about the quadratic formula.

This is the aops answer :)

8 0
2 years ago
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